如果联系人只有一个电话号码,我想选择它。如果它有超过1个电话号码,那么我想显示详细的联系卡。
我正在使用以下方法,它工作正常。
- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person {
if (person != nil) {
ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
if (ABMultiValueGetCount(phoneNumbers) == 1) {
//Do stuff to select phone number
}
}
}
然后,我实施此实用程序方法以显示详细联系人卡片:
- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier {
NSString* phone = nil;
ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
if (ABMultiValueGetCount(phoneNumbers) > 0) {
CFIndex index = ABMultiValueGetIndexForIdentifier(phoneNumbers, identifier);
phone = (__bridge_transfer NSString*)ABMultiValueCopyValueAtIndex(phoneNumbers, index);
}
}
但这个方法永远不会被调用? 如果我注释掉第一个方法,那么第二个方法就会被调用。我怎么能同时打电话,还是有另一种方式来实现这个目标?
答案 0 :(得分:0)
解决方法是在开始predicate
之前添加peoplePicker
,在这种情况下它将是:
-(void)getContacts {
ABPeoplePickerNavigationController *peoplePicker = [[ABPeoplePickerNavigationController alloc] init];
peoplePicker.peoplePickerDelegate = self;
if ([peoplePicker respondsToSelector:@selector(setPredicateForSelectionOfPerson:)])
{
// The people picker will select a person that has exactly one phone number and call peoplePickerNavigationController:didSelectPerson:,
// otherwise the people picker will present an ABPersonViewController for the user to pick one of the Phone Numbers.
peoplePicker.predicateForSelectionOfPerson = [NSPredicate predicateWithFormat:@"phoneNumbers.@count = 1"];
}
[self presentViewController:peoplePicker animated:NO completion:nil];
}
同样,对于emailAdresses,请将@"phoneNumbers.@count = 1"
替换为@"emailAddresses.@count = 1"
。