伪造“点”运算符在C ++中重载

Question

我认为这是一个愚蠢的问题，并且有很多充分的理由不应该考虑这样的事情，但是现在让我们忽略它......

我知道一个人不能超载＆＃34; dot＆＃34; C ++中的运算符。 C ++在反射功能方面也缺乏，因此提供在编译时尝试伪造它的方法也很棘手......

无论如何，现在让我以一个例子的形式提出这个问题：

class Foo
{
...
public:
    int bar();
...
};

template <class T>
class Bar
{
    T* m_ptr; // perhaps use an unique_ptr for safety.
...
public:
    Bar(T* ptr) : m_ptr(ptr) { } // create a local copy instead
    int qux();
... 
}

int main()
{
    Foo quux;
    Bar corge(&quux);
    corge.bar(); // I want to do this instead of corge->bar();
    corge.qux(); // without losing this functionality!
                 // Is there a way to do such a thing?
                 // my expectations: \(^.^)/
                 // what is probably the sad truth: /(;.;)\
                 // Also, I realize there should be no good reason to do this...
                 // Just pretend I have a really really REALLY good reason to want to do this :P
                 // Thanks!! :D
}