Question

允许用户提交配对
允许用户删除配对
允许用户提交最终配对

如何编辑程序以便用户（在完成1,2或3之后）再次询问相同的问题？（问题= user_selection）

clue_list = {'#':'A', '%':'N', '*':'M'}

user_selection = input('What would you like to do? 1.Submit a letter or symbol pairing,     2.Delete a letter/symbol pairing, 3. Submit Final Answers ')
while user_selection != '3':
if user_selection == '1':
    userkey = input('Please enter a symbol to add: ')
    uservalue = input('Please enter a letter to add: ')
    if userkey in clue_list:
        print('This symbol has already been matched. Please try again.')
    else:
        clue_list[userkey] = uservalue
    print(clue_list)
if user_selection == '2':
    user_delete_input = input('What letter/symbol would you like to delete? (Please enter symbol to delete the pairing ')
    if user_delete_input in clue_list:
        del clue_list[user_delete_input]
        print('That letter/symbol has been deleted.')
    else:
        print('Error: That letter/symbol has not been found in file.')                

user_submit1 = input('Would you like to submit more pairings? Yes/No ')
if user_submit1 == 'Yes':
    function_result2 = submit(clue_list)
else:
    if user_submit1 == 'No':
       print('...')

Answer 1

问题的关键在于重复选择过程。如果您学习使用函数抽象出部分代码，则可以非常轻松地完成此操作。例如，您的问题的可能答案如下：

while True:
    user_selection = input(msg_ask).strip()
    if   user_selection == '1': add_symbol(clue_list)
    elif user_selection == '2': remove_symbol(clue_list)
    elif user_selection == '3': break

我们已经定义了add_symbol和remove_symbol这样的函数：

clue_list = {'#':'A', '%':'N', '*':'M'}

msg_ask = '''
What would you like to do?
1. Submit a letter or symbol pairing,
2. Delete a letter/symbol pairing,
3. Submit Final Answers
'''

def add_symbol(clue_list):
    userkey = input('Please enter a symbol to add: ')
    uservalue = input('Please enter a letter to add: ')
    if userkey in clue_list:
        print('This symbol has already been matched.')
    else:
        clue_list[userkey] = uservalue
        print(clue_list)

def remove_symbol(clue_list):
    msg = 'What letter/symbol would you like to delete? (Please enter symbol to delete the pairing) '
    user_delete_input = input(msg)
    if user_delete_input in clue_list:
        del clue_list[user_delete_input]
        print('That letter/symbol has been deleted.')
    else:
        print('Error: That letter/symbol has not been found in file.')

您会注意到第一个代码块更容易阅读。

如何循环答案，以便如果用户输入1,2或3并执行该功能，它会再次询问他们的选择？

1 个答案: