Question

我想知道我是否可以使用PTHREAD_MUTEX_ERRORCHECK互斥锁自行创建递归互斥锁类型，结果如下：

typedef struct {
    pthread_mutex_t mutex;
    uint32_t deadlocks;
} pthread_recursivemutex_t;

int pthread_recursivemutex_init(pthread_recursivemutex_t *mutex)
{
    int ret;
    pthread_mutexattr_t attr;

    mutex->deadlocks = 0;

    ret = pthread_mutexattr_init(&attr);

    if (ret != 0) {
        return ret;
    }

    (void)pthread_mutexattr_settype(&attr, PTHREAD_MUTEX_ERRORCHECK);

    ret = pthread_mutex_init(&mutex->mutex, &attr);

    (void)pthread_mutexattr_destroy(&attr);

    return ret;
}

void pthread_recursivemutex_lock(pthread_recursivemutex_t *mutex)
{
    int ret;    

    ret = pthread_mutex_lock(&mutex->mutex);

    if (ret == 0) {
        mutex->deadlocks = 0;
    } else if (ret == EDEADLK) {
        mutex->deadlocks += 1;
    }
}

void pthread_recursivemutex_unlock(pthread_recursivemutex_t *mutex)
{
    if (mutex->deadlocks == 0) {
        (void)pthread_mutex_unlock(&mutex->mutex);
    } else {
        mutex->deadlocks -= 1;
    }
}

void pthread_recursivemutex_destroy(pthread_recursivemutex_t *mutex)
{
    (void)pthread_mutex_destroy(&mutex->mutex);
}

我发现这种类型的递归互斥锁比具有PTHREAD_MUTEX_RECURSIVE属性的互斥锁快得多：

iterations               : 1000000

pthread_mutex_t          : 71757 μSeconds
pthread_recursivemutex_t : 48583 μSeconds

测试代码（每次调用1000000次）：

void mutex_test()
{
    pthread_mutex_lock(&recursiveMutex);
    pthread_mutex_lock(&recursiveMutex);
    pthread_mutex_unlock(&recursiveMutex);
    pthread_mutex_unlock(&recursiveMutex);
}

void recursivemutex_test()
{
    pthread_recursivemutex_lock(&myMutex);
    pthread_recursivemutex_lock(&myMutex);
    pthread_recursivemutex_unlock(&myMutex);
    pthread_recursivemutex_unlock(&myMutex);
}

pthread_recursivemutex_t几乎是pthread_mutex_t的两倍？但两者的行为方式相同......？

顺便说一句：

pthread_mutex_t my_mutex;

void *m(void*a)
{
    printf("m: %d %d\n", pthread_mutex_lock(&my_mutex), EDEADLK);
    usleep(500 * 1000);
    printf("m: %d\n", pthread_mutex_lock(&my_mutex));
    pthread_mutex_unlock(&my_mutex);

    return a;
}

void *m2(void *a)
{
    printf("UNLOCKED!!: %d\n", pthread_mutex_lock(&my_mutex));
    usleep(500 * 1000);
    printf("m2: %d\n", pthread_mutex_lock(&my_mutex));

    return a;
}

int main(int argc, const char * argv[])
{
    pthread_t t,t2;
    pthread_mutexattr_t attr;
    pthread_mutexattr_init(&attr);
    pthread_mutexattr_settype(&attr, PTHREAD_MUTEX_ERRORCHECK);
    pthread_mutex_init(&my_mutex, &attr);

    pthread_create(&t, NULL, m, NULL);
    pthread_create(&t2, NULL, m2, NULL);

    pthread_join(t, NULL);
    pthread_join(t2, NULL);

    return 0;
}

给出

m: 0 11 m: 11 UNLOCKED!!: 0 m2: 11

这意味着线程2在锁定时无法获取互斥锁。

我的递归互斥锁vs pthread_mutex_t（类型：递归）（重新发布，推送）

0 个答案: