我有UIView
touchesBegan:withEvent:
处理触摸,此UIView位于UITableViewCell
。
当我触摸它时没有任何反应,当我“长按”它然后触摸事件被触发。
我跳过了设置吗?我可以做些什么来立即反应我的UIView
?
这是代码:
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
UITouch *touch = [touches anyObject];
CGPoint touchLocation = [touch locationInView:self];
[self handleTouchAtLocation:touchLocation];
}
当我把NSLog放到这个方法时,这就是跟踪的内容(格式化是我的):
touchesBegan:touches withEvent:<UITouchesEvent: 0x170078f00>
timestamp: 281850 touches: {(
<UITouch: 0x1781486c0>
phase: Began tap
count: 1 window: <UIWindow: 0x145e0ab30;
frame = (0 0; 320 568);
gestureRecognizers = <NSArray: 0x178240720>;
layer = <UIWindowLayer: 0x17802b800>>
view: <CSRateView: 0x145d49850;
frame = (50 54; 220 40);
autoresize = TM;
layer = <CALayer: 0x17003c0c0>>
location in window: {207, 81}
previous location in window: {207, 81}
location in view: {157, 7}
previous location in view: {157, 7}
)}
答案 0 :(得分:3)
禁用tableView的delaysContentTouches
self.tableView.delaysContentTouches = NO;
然后,在你的细胞类:
@implementation MyCell
- (void)awakeFromNib
{
for (id view in self.subviews) {
if ([view respondsToSelector:@selector(setDelaysContentTouches:)]){
[view setDelaysContentTouches:NO];
}
}
}
@end
- 编辑 -
或在UITableViewCell上创建一个类别
#import "UITableViewCell+DelayTouches.h"
@implementation UITableViewCell (DelayTouches)
- (void)setDelayContentTouches:(BOOL)enable
{
for (id view in self.subviews) {
if ([view respondsToSelector:@selector(setDelaysContentTouches:)]){
[view setDelaysContentTouches:enable];
}
}
}
@end
并在cellForRow:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell *cell = ...
[cell setDelayContentTouches:NO];
return cell;
}