Question

我想把Curl写成java：

curl -X PUT -u username:password http://localhost:80/api/client/include/clientID

多数民众赞成我用Google搜索但我的问题是如何将client_id和client的值传递给put，因为它们之间存在/ include。我对如何写卷曲感到有点困惑。任何人都可以帮助我吗？

public String RestPutClient(String url, int newValue, int newValue2) {
            // example url : http://localhost:80/api/
            DefaultHttpClient httpClient = new DefaultHttpClient();
            StringBuilder result = new StringBuilder();
            try {
                HttpPut putRequest = new HttpPut(url);
                putRequest.addHeader("Content-Type", "application/json");
                putRequest.addHeader("Accept", "application/json");
                JSONObject keyArg = new JSONObject();
                keyArg.put("value1", newValue);
                keyArg.put("value2", newValue2);
                StringEntity input;
                try {
                    input = new StringEntity(keyArg.toString());
                } catch (UnsupportedEncodingException e) {
                    e.printStackTrace();
                    return success;
                }
                putRequest.setEntity(input);
                HttpResponse response = httpClient.execute(putRequest);
                if (response.getStatusLine().getStatusCode() != 200) {
                    throw new RuntimeException("Failed : HTTP error code : "
                            + response.getStatusLine().getStatusCode());
                }
                BufferedReader br = new BufferedReader(new InputStreamReader(
                        (response.getEntity().getContent())));
                String output;
                while ((output = br.readLine()) != null) {
                    result.append(output);
                }
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return result.toString();
        }

Answer 1

我假设您传递的参数应该代表客户端和clientID。您只需构建从参数传递给HttpPut的URL。

如果这些是你的参数

url = "http://localhost:80/api/";
newValue = "client";
newValue2 = "clientID";

然后您的HttpPut初始化将如下所示

HttpPut putRequest = new HttpPut(url + newValue + "/include/" + newValue2);

另见： How do I concatenate two strings in Java?

如何将httpput写入java

1 个答案: