我试图做一个HTTPPut,但似乎我无法实例化HTTPPut对象。我将此问题称为源代码,但似乎创建了一个HTTPPut对象,我需要一个URI而不是一个URL?有人能告诉我如何实例化HTTPPut对象吗?
来源:
URL url;
try {
url = new URL(Constants.API_URL + "api/documents/"
+ mustRead.getContract_id()
+ "/mark_as_read");
HttpClient client = new DefaultHttpClient();
HttpPut put = new HttpPut(url);
List<NameValuePair> pairs = new ArrayList<NameValuePair>();
pairs.add(new BasicNameValuePair("contract_id",
mustRead.getContract_id() + ""));
pairs.add(new BasicNameValuePair("time", URLEncoder
.encode(currentDateandTime)));
put.setEntity(new UrlEncodedFormEntity(pairs));
HttpResponse response = client.execute(put);
Log.v("--", response.getStatusLine()
.getStatusCode() + " ST");
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
我在这一行上遇到了这个问题:HttpPut put = new HttpPut(url);
我应该用一些图书馆这样做吗?现在我导入import org.apache.http.client.methods.HttpPut;
答案 0 :(得分:0)
您有两种选择:创建URI而不是URL对象,或者只使用字符串:
HttpPut put = new HttpPut(Constants.API_URL + "api/documents/"
+ mustRead.getContract_id()
+ "/mark_as_read");