我正在尝试创建一个新的线程gpsthread,它应该在后台运行,并存储该值。
class gpsthread: public QThread{
Q_OBJECT
private:nrega_status_t status2;
public:
explicit gpsthread(QObject *parent = 0):QThread(parent) {
// QTimer *t = new QTimer(this);
// connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
// t->start(10000);
}
void run(){
qDebug()<<"inside gps thread\n";
QTimer *t = new QTimer(this);
connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
t->start(10000);
}
public slots:void processgps(){
int status2;
status2=gps_management();
}
};
我的主要课程是快速浏览。
int main(int argc, char *argv[])
{
QString file = "qml/main.qml";
QApplication app(argc, argv);
TranslationTest myObj;
QuickView view;
subthread object;
gpsthread obj;
gprsthread gprs;
view.rootContext()->setContextProperty("rootItem", (QObject *)&myObj);
obj.start();
//from subthread
QObject::connect(&object, SIGNAL(batterytoqml(QVariant,QVariant)),item, SLOT(frombattery(QVariant,QVariant)));
QObject::connect(&gprs, SIGNAL(gprstoqml(QVariant)),item, SLOT(fromgprs(QVariant)));
return app.exec();
}
我也试过这个
class gpsthread: public QThread{
Q_OBJECT
private:nrega_status_t status2;
public:QTimer* t;
explicit gpsthread(QObject *parent = 0):QThread(parent) {
// QTimer *t = new QTimer(this);
// connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
// t->start(10000);
}
void run(){
qDebug()<<"inside gps thread\n";
t = new QTimer(this);
connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
t->start(10000);
exec();
}
public slots:void processgps(){
int status2;
status2=gps_management();
}
};
但提出错误
QObject: Cannot create children for a parent that is in a different thread
如果我在构造函数中创建对象,那么它也会给出相同的错误,因为该对象将在主线程中创建。 怎么解决这个?
答案 0 :(得分:6)
不推荐使用QThread继承。 QThread是一个运行事件循环的完整类,通常是您需要的。 documentation建议使用从QObject继承并在插槽中工作的worker对象。工人被转移到QThread。发送连接信号时,插槽将以正确的线程运行。
class gpsworker: public QObject
{
Q_OBJECT
public:
explicit gpsworker(QObject *parent = 0):
QObject(parent)
{}
public slots:
void processgps() {
qDebug() << "processgps()" << QThread::currentThreadId();
}
}
void OwnerClass::startWorker() {
QTimer *timer = new QTimer(this);
QThread *thread = new QThread(this);
this->worker = new gpsworker();
this->worker->moveToThread(thread);
connect(timer, SIGNAL(timeout()), this->worker, SLOT(processgps()) );
connect(thread, SIGNAL(finished()), this->worker, SLOT(deleteLater()) );
thread->start();
timer->start();
}
如果您希望计时器也在其他线程中,QTimer::start
是一个插槽。
答案 1 :(得分:1)
QObject: Cannot create children for a parent that is in a different thready
是t = new QTimer(this)
中的run()
正在子线程中创建一个对象,但this
处的gpsthread
是在主线程中。一个简单的解决方案是t = new QTimer()
没有父级,并删除析构函数中的计时器。这是一个例子:
class gpsthread : public QThread {
Q_OBJECT
public:
explicit gpsthread(QObject *parent = 0):
QThread(parent)
,timer(NULL) {
qDebug() << "Parent thread" << QThread::currentThreadId();
}
~gpsthread() {
quit();
wait();
delete timer;
}
protected:
void run() {
qDebug() << "Inside gps thread" << QThread::currentThreadId();
timer = new QTimer; // no parent
connect(timer, SIGNAL(timeout()), this, SLOT(processgps()));
timer->start(1000);
exec();
}
public slots:
void processgps() {
qDebug() << "processgps()" << QThread::currentThreadId();
}
private:
QTimer *timer;
};
很快你会发现控制台打印:
Parent thread 0x3b28
inside gps thread 0x3f10
processgps() 0x3b28
processgps() 0x3b28
processgps() 0x3b28
processgps() 0x3b28
这意味着processgps()
在您的子线程中无效。这是因为此插槽是gpsthread
的成员,它位于主线程中。一个简单的解决方案是直接调用processgps()
并使用sleep()
作为计时器:
class gpsthread : public QThread
{
Q_OBJECT
public:
explicit gpsthread(QObject *parent = 0):
QThread(parent)
, abort(false) {
qDebug() << "Parent thread" << QThread::currentThreadId();
}
~gpsthread() {
abort = true;
wait();
}
protected:
void run() {
while(!abort) {
sleep(1);
processgps();
}
}
public slots:
void processgps() {
qDebug() << "processgps()" << QThread::currentThreadId();
}
private:
bool abort;
};
这不是一个好的解决方案,推荐的方法是创建一个工作人员完成所有工作,然后使用QObject::moveToThread()中所述的QThread Document