Question

我想做这样的事情：

def results = Item.findAll("from Item c, Tag b, ItemTag a where c = a.item and  b = a.tag and (b.tag like :q or c.uri like :q) " + ob,[q:q])
def items = (Item) results[0..1][0]

但我得到

Cannot cast object '[Ljava.lang.Object;@1e224a5' with class '[Ljava.lang.Object;' to class 'org.maflt.ibidem.Item'

我可以得到我需要的东西，但它似乎不是最好的解决方案：

def items = [] as Set
def cnt = results.size()
for (i=0;i<cnt-1;i++) { items << results[i][0] }
items = items as List

更新

解决方案建议使用

def results = Item.findAll("from Item c, Tag b, ItemTag a where c = a.item and  b = a.tag and (b.tag like :q or c.uri like :q) " + ob,[q:q])    
def items = results[0] as List

不起作用。该查询实际上生成了正确的SQL：

select
    item0_.id as id3_0_,
    tag1_.id as id16_1_,
    itemtag2_.id as id6_2_,
    item0_.version as version3_0_,
    item0_.last_updated as last3_3_0_,
    item0_.docsize as docsize3_0_,
    item0_.customer_id as customer5_3_0_,
    item0_.uri as uri3_0_,
    item0_.created_by_person_id as created7_3_0_,
    item0_.updated_by_person_id as updated8_3_0_,
    item0_.md5 as md9_3_0_,
    item0_.original_file_name as original10_3_0_,
    item0_.date_created as date11_3_0_,
    item0_.doctype as doctype3_0_,
    item0_.identifier as identifier3_0_,
    tag1_.version as version16_1_,
    tag1_.tagtype_id as tagtype3_16_1_,
    tag1_.tag as tag16_1_,
    tag1_.last_updated as last5_16_1_,
    tag1_.customer_id as customer6_16_1_,
    tag1_.created_by_person_id as created7_16_1_,
    tag1_.updated_by_person_id as updated8_16_1_,
    tag1_.date_created as date9_16_1_,
    itemtag2_.version as version6_2_,
    itemtag2_.updated_by_person_id as updated3_6_2_,
    itemtag2_.weight as weight6_2_,
    itemtag2_.tag_id as tag5_6_2_,
    itemtag2_.item_id as item6_6_2_,
    itemtag2_.last_updated as last7_6_2_,
    itemtag2_.date_created as date8_6_2_,
    itemtag2_.source_id as source9_6_2_,
    itemtag2_.created_by_person_id as created10_6_2_ 
from
    item item0_,
    tag tag1_,
    item_tag itemtag2_
where
    item0_.id=itemtag2_.item_id
    and tag1_.id=itemtag2_.tag_id
    and (
        lower(tag1_.tag) like '%english%'
        or lower(item0_.original_file_name) like '%english%'
    ) 
order by
     item0_.id

但不幸的是，items = results [0]因为List不起作用。它只返回3行，只有item [0]是一个Item。

items.each{println it.class}

给出：

class org.maflt.ibidem.Item
class org.maflt.ibidem.Tag
class org.maflt.ibidem.ItemTag

Answer 1

当您的HQL选择多个实体时，您应该更具体。以下内容应仅返回项目：

def items = Item.executeQuery("select c from Item as c, Tag as b, ItemTag as a where c = a.item and  b = a.tag and (b.tag like :q or c.uri like :q) " + ob,[q:q])

干杯！

是否可以施放范围

1 个答案: