我正在尝试重新定位this或this,但我一直收到错误,我无法修复...
首先,这是我的依赖项:
compile 'io.spray:spray-can_2.11:1.3.1'
compile 'io.spray:spray-routing_2.11:1.3.1',
compile 'io.spray:spray-json_2.11:1.2.6'
现在我要做的是:
class WHttpService extends Actor with HttpService with ActorLogging {
implicit def actorRefFactory = context
def receive = runRoute(route)
lazy val route = logRequest(showReq _) {
// Way too much imports but I tried all I could find
import spray.json._
import DefaultJsonProtocol._
import MasterJsonProtocol._
import spray.httpx.SprayJsonSupport._
path("server" / Segment / DoubleNumber / DoubleNumber) { (login, first, second) =>
get {
complete {
Answer(1, "test")
}
}
}
}
private def showReq(req : HttpRequest) = LogEntry(req.uri, InfoLevel)
}
使用:
case object MasterJsonProtocol extends DefaultJsonProtocol with SprayJsonSupport {
import spray.json._
case class Answer(code: Int, content: String)
implicit val anwserFormat: JsonFormat[Answer] = jsonFormat2(Answer)
}
现在我收到了这个错误:
Error:(42, 19) type mismatch;
found : MasterJsonProtocol.Answer
required: spray.httpx.marshalling.ToResponseMarshallable
Answer(1, "test")
^
我尝试过很多东西但却无法让它发挥作用。 我试过
Answer(1, "test").toJson
Answer(1, "test").toJson.asJsObject
最后我做的是
complete {
Answer(1, "test").toJson.compactPrint
}
这有效,但当我需要application / json时,它会以Content-Type:text / plain的形式发送给客户端。
任何人都能看到问题所在吗?
编辑:我在github上添加了一个示例项目https://github.com/ydemartino/spray-test
答案 0 :(得分:4)
将模型移到json协议之外,使其成为常规对象(不是案例对象)
case class Answer(code: Int, content: String)
object MasterJsonProtocol extends DefaultJsonProtocol {
implicit val anwserFormat = jsonFormat2(Answer)
}
修改强>
同时清理你的进口商品:
class WHttpService extends Actor with HttpService with ActorLogging {
implicit def actorRefFactory = context
def receive = runRoute(route)
lazy val route = logRequest(showReq _) {
// Way too much imports but I tried all I could find
import MasterJsonProtocol._
import spray.httpx.SprayJsonSupport._
path("server" / Segment / DoubleNumber / DoubleNumber) { (login, first, second) =>
get {
complete {
Answer(1, "test")
}
}
}
}
private def showReq(req : HttpRequest) = LogEntry(req.uri, InfoLevel)
}
答案 1 :(得分:2)
我创建了一个拉取请求来解决您的问题:https://github.com/ydemartino/spray-test/pull/1
必须先声明json协议对象,然后才能隐式使用它。我不完全确定为什么编译器无法弄清楚,但是将对象声明移到顶部会修复它。
对于您的实际项目,请确保在每个文件中声明包,然后在import语句中使用这些包。
答案 2 :(得分:0)
在我的例子中,不可解析的隐式格式实例的名称与本地定义冲突,因此它被遮蔽了。编译器对此非常缄默。只是在经过几个小时的撞击之后才意外发现。