如何将AB2468123
与excel-vba
我尝试了以下几点:
myStr = "AB2468123"
split(myStr, "1" OR "2" OR "3"......."9")
我只想获得字母(字母)。
感谢。
答案 0 :(得分:4)
这是我发现的最好的方法。它可能有点基础,但它确实起作用:)
Function Split_String(Optional test As String = "ABC111111") As Variant
For i = 1 To Len(test)
letter = Mid(test, i, 1)
If IsNumeric(letter) = True Then
justletters = Left(test, i - 1)
justnumbers = Right(test, Len(test) - (i - 1))
Exit For
End If
Next
'MsgBox (justnumbers)
'MsgBox (justletters)
'just comment away the answer you want to have :)
'Split_String = justnumbers
'Split_String = justletters
End Function
答案 1 :(得分:3)
如何只检索输入字符串中的字母:
Function GetLettersOnly(str As String) As String
Dim i As Long, letters As String, letter As String
letters = vbNullString
For i = 1 To Len(str)
letter = VBA.Mid$(str, i, 1)
If Asc(LCase(letter)) >= 97 And Asc(LCase(letter)) <= 122 Then
letters = letters + letter
End If
Next
GetLettersOnly = letters
End Function
Sub Test()
Debug.Print GetLettersOnly("abc123") // prints "abc"
Debug.Print GetLettersOnly("ABC123") // prints "ABC"
Debug.Print GetLettersOnly("123") // prints nothing
Debug.Print GetLettersOnly("abc123def") // prints "abcdef"
End Sub
完整性 编辑(和Chris Neilsen)这里是Regex
方式:
Function GetLettersOnly(str As String) As String
Dim result As String, objRegEx As Object, match As Object
Set objRegEx = CreateObject("vbscript.regexp")
objRegEx.Pattern = "[a-zA-Z]+"
objRegEx.Global = True
objRegEx.IgnoreCase = True
If objRegEx.test(str) Then
Set match = objRegEx.Execute(str)
GetLettersOnly = match(0)
End If
End Function
Sub test()
Debug.Print GetLettersOnly("abc123") //prints "abc"
End Sub
答案 2 :(得分:3)
更简单的单发RegExp
Sub TestIt()
MsgBox CleanStr("AB2468123")
End Sub
Function CleanStr(strIn As String) As String
Dim objRegex As Object
Set objRegex = CreateObject("vbscript.regexp")
With objRegex
.Pattern = "[^a-zA-Z]+"
.Global = True
CleanStr = .Replace(strIn, vbNullString)
End With
End Function
答案 3 :(得分:0)
可能最快的方法是解析Byte String:
Function alpha(txt As String) As String
Dim b, bytes() As Byte: bytes = txt
For Each b In bytes
If Chr(b) Like "[A-Za-z]" Then alpha = alpha & Chr(b)
Next b
End Function