Question

给定XML，其中FORMNUMBER只能是数字;从数字开始，然后包括alpha;或遵循数字字母数字模式：

<FORMSLIST>
    <FORMS>
        <FORMNUMBER>3 ABC</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 ABC 45</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 XYZ</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>18</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>326</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>21 B</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 EFG 79</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 ABCD</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
</FORMSLIST>

这是我的样式表（Alphanumeric sort on mixed string value revisited上的变体）：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="/">
        <xsl:variable name="vAlpha" select="' ABCDEFGHIJKLMNOPQRSTUVWXYZ'"/>
        <xsl:for-each-group select="FORMSLIST/FORMS" group-by="FORMSEQ">
            <xsl:sort select="FORMSEQ" data-type="number"/>
            <!-- NEED HELP WITH THE FOLLOWING SORT -->
            <xsl:for-each select="current-group()[(floor(number(FORMNUMBER)) = floor(number(FORMNUMBER))) or (substring-before(FORMNUMBER,' ') and translate(substring-before(FORMNUMBER,' '),' 0123456789','') = '')]">
                <xsl:sort select="translate(FORMNUMBER, $vAlpha, '')" data-type="number"/>
                <xsl:sort select="substring-after(FORMNUMBER,' ')"/>
                <xsl:element name="{local-name()}">
                    <xsl:copy-of select="*"/>
                </xsl:element>
            </xsl:for-each>
            <!-- THIS SORT WORKS AND I DON'T HAVE QUESTIONS ON THIS: ALPHA ONLY FORMS; BEGIN WITH ALPHA AND THEN GO TO NUMERIC...MAY ALSO GO BACK TO ALPHA -->
            <xsl:for-each select="current-group()[contains($vAlpha,substring(FORMNUMBER,1,1)) or (translate(FORMNUMBER, $vAlpha, '') = '')]">
                <xsl:sort select="translate(FORMNUMBER, ' 0123456789', '')"/>
                <xsl:sort select="translate(FORMNUMBER, $vAlpha, '')" data-type="number"/>
                <xsl:element name="{local-name()}">
                    <xsl:copy-of select="*"/>
                </xsl:element>
            </xsl:for-each>
        </xsl:for-each-group>
    </xsl:template>
</xsl:stylesheet>

结果转换为：

<FORMSLIST>
    <FORMS>
        <FORMNUMBER>3 ABC</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 ABCD</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 XYZ</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>18</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>21 B</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>326</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 ABC 45</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 EFG 79</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
</FORMSLIST>

我想要的结果是将'12 ABC 45'和'12 EFG 79'表格包含在这样的排序中（列表首先按开头编号排序）：

<FORMSLIST>
    <FORMS>
        <FORMNUMBER>3 ABC</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 ABCD</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>3 XYZ</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 ABC 45</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>12 EFG 79</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>18</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>21 B</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
    <FORMS>
        <FORMNUMBER>326</FORMNUMBER>
        <FORMSEQ>99900</FORMSEQ>
    </FORMS>
</FORMSLIST>

我尝试了很多变化，但似乎无法让它发挥作用。

Answer 1

在XSLT 2.0中，tokenize（FORMNUMBER，''）返回由FORMNUMBER中的空格分隔的标记序列。因此，您可以使用这些<xsl:sort>元素：

            <xsl:sort select="tokenize(FORMNUMBER, ' ')[1]" data-type="number"/>
            <xsl:sort select="tokenize(FORMNUMBER, ' ')[2]" />
            <xsl:sort select="tokenize(FORMNUMBER, ' ')[3]" data-type="number"/>

未测试。但看起来它会完全符合您的要求。

混合字符串值的字母数字排序：字母数字alpha

1 个答案: