Question

它适用于app引擎的blobstore，因为它的上传界面每次都会生成一个临时端点。我想从前端获取复杂性，Flask会接受post请求并将其转发到blobstore指定的端点。性能和流量成本根本不是问题，有人可以推荐一种最直接的方式来实现吗？

Answer 1

查看the docs for the BlobStore flow看起来您需要做的就是自己接受该文件，然后将其发送到create_upload_url指定的端点：

@app.route("/upload-complete", methods=["POST"])
def handle_upload_response():
    """This will be called after every upload, but we can ignore it"""
    return "Success"

@app.route("/upload", methods=["POST"])
def upload():
    fp = request.files["name_of_file"]
    url = create_upload_url(url_for('handle_upload_response'))
    response = requests.post(url, {'file':
                                   (fp.filename, fp.stream,
                                    fp.content_type, fp.headers)})
    if response == "Success":
        return "File uploaded successfully"
    else:
        return "Something didn't work out"

使用Flask作为传递代理进行文件上传？

1 个答案: