Question

我从Servlet开始，我不明白我的问题。我称之为Servlet感谢JQuery，我希望Servlet将数据返回给JS。

我的JS代码：

$.ajax({
    url:'http://localhost:8080/hello/servlet',
    data:'{field:"abc"}',
    type:'post',
    cache:false,
    success:function(data){alert(data);},
    error:function(){alert('error');}
}
);

和我的Servlet：

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class HelloServlet extends HttpServlet{
        protected void doGet(HttpServletRequest req, HttpServletResponse response)
            throws ServletException, IOException
        {
  //Do nothing  import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

public class HelloServlet extends HttpServlet
{
    protected void doGet(HttpServletRequest req, HttpServletResponse response)
        throws ServletException, IOException
    {
        //Do nothing
    }

    protected void doPost(HttpServletRequest req, HttpServletResponse response)
        throws ServletException, IOException
    {
        String field = req.getParameter("field");
        PrintWriter out = response.getWriter();

        response.setContentType("text/html");
        response.setHeader("Cache-control", "no-cache, no-store");
        response.setHeader("Pragma", "no-cache");
        response.setHeader("Expires", "-1");

        response.setHeader("Access-Control-Allow-Origin", "*");
        response.setHeader("Access-Control-Allow-Methods", "POST");
        response.setHeader("Access-Control-Allow-Headers", "Content-Type");
        response.setHeader("Access-Control-Max-Age", "86400");


        out.println("<html>");
        out.println("<body>");
        out.println("You entered \"" + field + "\" into the text box.");
        out.println("</body>");
        out.println("</html>");
    }
}

servlet什么都不返回...... 问题是什么？

仅供参考，当我在浏览器中访问localhost：8080 / hello / servlet时，它可以工作。

使用ajax调用Servlet并返回响应（JQuery）

0 个答案: