AJAX POST Servlet调用

Question

我需要像这样将网址确切地发布到下一页。

http://localhost:9000/favorite.json?url1=/offers/singapore-rugby-7s&url2=/offers/limited-time-offer-save-up-to-40&url3=/offers/rejoice-this-easter&url4=/06-offers-detail

下面的代码可以工作吗？不确定我的方法是否正确。

var formattedFavouriteOffer = '?url1=/offers/singapore-rugby-7s&url2=/offers/limited-time-offer-save-up-to-40&url3=/offers/rejoice-this-easter&url4=/06-offers-detail';

$.ajax({
    type: 'POST',
    url: "http://localhost:9000/favorite.json" +formattedFavouriteOffer,
    data: formattedFavouriteOffer,
    dataType: "text",
    success: function(resultData) { 
        alert("Save Complete"); 
    }
});