Java 1.4等效于javax.net.ssl.SSLContext.setDefault（context）;

Question

我正在努力纠正一些必须能够在Java 1.4应用服务器中运行的旧Java应用程序代码的问题。

该应用程序正在调用SOAP WebService，并且必须传递客户端证书。该应用程序正在与许多其他应用程序共享服务器，因此我尝试使用自定义密钥管理器进行连接。下面的代码适用于较新版本的Java，但“setDefault”在1.6中引入。当我尝试编译时，它导致无法找到符号错误。

    javax.net.ssl.SSLContext context = javax.net.ssl.SSLContext.getInstance("SSL");
    context.init(getKeyManagers(), (TrustManager[]) getKeyManagers(), null);
    SSLContext.setDefault(context);

那么，在Java 1.4中，什么相当于“SSLContext.setDefault（context）;”？

谢谢， 道格

以下是我正在尝试做的其他代码：

private org.apache.axis.message.SOAPEnvelope SendSOAP(String SOAPaction,
        String EndPointURL, String SOAPmessage) {

    TrustManager[] trustAllCerts = new TrustManager[] { new X509TrustManager() {
        public X509Certificate[] getAcceptedIssuers() {
            // TODO Auto-generated method stub
            return null;
        }

        public void checkServerTrusted(X509Certificate[] arg0, String arg1)
                throws CertificateException {
            // TODO Auto-generated method stub
        }

        public void checkClientTrusted(X509Certificate[] arg0, String arg1)
                throws CertificateException {
            // TODO Auto-generated method stub
        }
    } };

    try {
        SSLContext context = SSLContext.getInstance("SSL");
        context.init(getKeyManagers(), trustAllCerts, null);
        SSLContext.setDefault(context);
    } catch (Exception e) {
        logger.fatal(e.toString());
    }


    org.apache.axis.message.SOAPEnvelope resp = null;
    try {
        InputStream input = new ByteArrayInputStream(SOAPmessage.getBytes());
        org.apache.axis.client.Service service = new org.apache.axis.client.Service();

        logger.debug(SOAPmessage);

        Call call = (Call) service.createCall();
        call.setSOAPActionURI(SOAPaction);
        call.setTargetEndpointAddress(new URL(EndPointURL));

        SOAPEnvelope env = new SOAPEnvelope(input);

        resp = call.invoke(env);
    } catch (Exception e) {
        e.printStackTrace();
        logger.fatal("Exception from send soap: " + e.toString());
        e.printStackTrace(System.out);
    }

    return resp;

}