Java NIO ByteBuffer:put和get字符串

时间:2014-07-08 14:08:10

标签: java

我有以下测试代码。我想知道如何放置,并使用Java NIO ByteBuffer获取String。 我在需要帮助的地方添加了两条评论。

package testPipe;

import java.io.UnsupportedEncodingException;
import java.nio.ByteBuffer;
import java.nio.charset.Charset;
import java.nio.charset.CharsetDecoder;
import java.nio.charset.CharsetEncoder;

public class TestMemBuff {

    static final String dataFile = "invoicedata";
    static final double[] prices = { 19.99, 9.99, 15.99, 3.99, 4.99 };
    static final int[] units = { 12, 8, 13, 29, 50 };
    static final String[] descs = { "Java T-shirt", "Java Mug",
            "Duke Juggling Dolls", "Java Pin", "Java Key Chain" };

    public static Charset charset = Charset.forName("UTF-8");
    public static CharsetEncoder encoder = charset.newEncoder();
    public static CharsetDecoder decoder = charset.newDecoder();

    public static void main(String[] args) throws UnsupportedEncodingException {

        double price;
        int unit;
        String desc;
        double total = 0.0;

        ByteBuffer buf = ByteBuffer.allocate(1024);


        for (int i = 0; i < prices.length; i++) {
            buf.putDouble(prices[i]);
            buf.putInt(units[i]);
            buf.asCharBuffer().put(descs[i]);           // Is it correct?
        }

        buf.flip();

        // INPUT
        while (buf.hasRemaining()) {

            price = buf.getDouble();
            unit = buf.getInt();
            desc =  buf.asCharBuffer().toString();       //This must be wrong!
            System.out.format("You ordered %d" + " units of %s at $%.2f%n",
                    unit, desc, price);
            total += unit * price;
        }
    }

}

这是执行时的输出:

You ordered 12 units of ????
[...]

等等。

感谢您的关注

2 个答案:

答案 0 :(得分:3)

写作部分:

for (int i = 0; i < prices.length; i++) {
    buf.putDouble(prices[i]);
    buf.putInt(units[i]);

    byte[] descsBytes = descs[i].getBytes();
    buf.putInt(descsBytes.length);
    buf.put(descsBytes);
}

阅读部分:

while (buf.hasRemaining()) {

    price = buf.getDouble();
    unit = buf.getInt();

    int len = buf.getInt();
    byte[] bytes = new byte[len]; 
    buf.get(bytes);
    desc = new String(bytes);

    System.out.format("You ordered %d" + " units of %s at $%.2f%n",
                unit, desc, price);
    total += unit * price;
}

答案 1 :(得分:1)

ByteBuffer.asCharBuffer()有一些自己的行为。它创建了一个新的缓冲区,它与ByteBuffer共享内容,但是有一个独立的位置和一个位置。限制。 所以CharBuffer上的put()和get()不会改变ByteBuffer上的位置!

所以,只要这不完全符合您的需要,我就不会使用ByteBuffer.asCharBuffer()

因此解决方案是将字节写入并读入原始的ByteBuffer:

buf.putInt(descs[i].length);
buf.put(descs[i].getBytes());`

再次读取字符串读取长度并自己分配字节[]:

int stringLength = buf.getInt();
byte[] bytes = new byte[stringLength];
buf.get(bytes);
desc = new String(bytes);