Question

我需要通过paymentRecordDate排序TranHist节点，然后按帐户余额排序。

我的xml如下：

<data>
    <Account>
          <accountNumber>12345</accountNumber>
          <balance>1400</balance>
    </Account>
    <Account>
          <accountNumber>6789</accountNumber>
          <balance>2000</balance>
    </Account>
    <TranHist>
          <accountNumber>12345</accountNumber>
          <paymentStatus>CL</paymentStatus>
          <paymentRecordDate>20141101</paymentRecordDate>
    </TranHist>
    <TranHist>
          <accountNumber>12345</accountNumber>
          <paymentStatus>CL</paymentStatus>
          <paymentRecordDate>20141201</paymentRecordDate>
    </TranHist>
    <TranHist>
          <accountNumber>6789</accountNumber>
          <paymentStatus>1</paymentStatus>
          <paymentRecordDate>20141201</paymentRecordDate>
    </TranHist>
<data>

我到目前为止的xslt：

<xsl:variable name="accounts" select="data/Account"/>

<xsl:for-each select="data/TranHist">
    <xsl:sort select="number(paymentRecordDate)" order="descending" />
    <xsl:sort select="$accounts[accountNumber = ????/accountNumber]/balance" order="descending" />
    <xsl:copy-of select="."/>
</xsl:for-each>

如何在for-each上下文的TransHist节点中引用accountNumber？

Answer 1

如何在TransHist节点中引用accountNumber 每个背景？

执行此操作的最佳方法是使用键。尝试：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:key name="acct" match="Account" use="accountNumber" />

<xsl:template match="/">
    <root>
        <xsl:for-each select="data/TranHist">
            <xsl:sort select="paymentRecordDate" data-type="number" order="descending"/>
            <xsl:sort select="key('acct', accountNumber)/balance" data-type="number" order="descending"/>
            <xsl:copy-of select="."/>
        </xsl:for-each>
    </root>
</xsl:template>

</xsl:stylesheet>

xslt：使用查找条件排序

1 个答案: