如何在2个类别的sql中显示最大值

时间：2014-07-04 10:24:04

标签： mysql sql

我现在有一张看起来像这样的表：

表siswa： 

create table siswa(nis char(4) primary key, nama char(20), jk char(1), tmpt_lahir char(10), tgl_lahir date, nm_wali char(20), alamat char(50));

插入表siswa： 

insert into siswa values('0001', 'budi', 'L', 'sekayu', '1994-05-30', 'yanto', 'kayuara'), ('0002', 'joko', 'L', 'lumpatan', '1995-05-28', 'usman', 'bailangu'), ('0003', 'santoso', 'L', 'kayuara', '1994-05-30', 'yanto', 'kayuara'), ('0004', 'susan', 'P', 'bailangu', '1995-03-02', 'michael', 'bailangu'), ('0005', 'marta', 'L', 'epil', '1995-05-07', 'yanto', 'sekayu'), ('0006', 'lusi', 'P', 'sekayu', '1995-03-02', 'budi', 'lumpatan'), ('0007', 'manap', 'L', 'lumpatan', '1995-05-28', 'abdul', 'kayuara'), ('0008', 'budi', 'L', 'kayuara', '1994-12-01', 'subhan', 'kayuara');

表mata_pljran 

create table mata_pljran(kd_mp char(10) primary key, nm_mp char(20), kelas char(2), semester char(10), kkm int);

插入表mata_pljran 

insert into mata_pljran values('10.01.001', 'matematika', '10', 'ganjil', '70'), ('10.01.002', 'bahasa indonesia', '10', 'ganjil', '80'), ('10.01.003', 'kewarganegaraan', '10', 'ganjil', '80'), ('10.01.004', 'agama', '10', 'ganjil', '80'), ('10.01.005', 'bahasa inggris', '10', 'ganjil', '65'), ('10.02.001', 'fisika', '10', 'genap', '65'), ('10.02.002', 'kimia', '10', 'genap', '70'), ('10.02.003', 'biologi', '10', 'genap', '70'), ('10.02.004', 'matematika', '10', 'genap', '70');

表nilai 

create table nilai( nis char(4), kd_mp char(10) , nk decimal(5,2), nuh decimal(5,2), nuts decimal(5,2), nuas decimal(5,2), akhir decimal(5,2) default null, primary key (nis,kd_mp), foreign key (nis) references siswa(nis) on update cascade on delete cascade, foreign key (kd_mp) references mata_pljran(kd_mp) on update cascade on delete cascade ); update nilai set akhir=nk*(0.15)+nuh*(0.15)+nuts*(0.3)+nuas*(0.4);

插入表nilai 

INSERT INTO `nilai` (`nis`, `kd_mp`, `nk`, `nuh`, `nuts`, `nuas`) VALUES ('0001', '10.01.001', '80.00', '75.00', '85.00', '90.00'), ('0001', '10.01.002', '85.00', '85.00', '85.00', '85.00'), ('0001', '10.01.003', '75.00', '90.00', '85.00', '85.00'), ('0001', '10.01.004', '90.00', '65.00', '85.00', '85.00'), ('0001', '10.01.005', '95.00', '55.00', '85.00', '85.00'), ('0002', '10.01.001', '65.00', '68.00', '85.00', '85.00'), ('0002', '10.01.002', '80.00', '78.00', '85.00', '85.00'), ('0002', '10.01.003', '95.00', '100.00', '85.00', '85.00'), ('0002', '10.01.004', '85.00', '98.00', '85.00', '95.00'), ('0003', '10.01.001', '90.00', '68.00', '85.00', '95.00'), ('0003', '10.01.002', '85.00', '76.00', '35.00', '68.00'), ('0003', '10.01.003', '45.00', '87.00', '20.00', '45.00'), ('0003', '10.01.004', '35.00', '65.00', '85.00', '75.00'), ('0003', '10.01.005', '85.00', '95.00', '85.00', '85.00'), ('0005', '10.01.001', '90.00', '65.00', '85.00', '90.00'), ('0005', '10.01.002', '85.00', '78.00', '85.00', '90.00'), ('0005', '10.01.003', '95.00', '98.00', '85.00', '90.00'), ('0005', '10.01.004', '85.00', '58.00', '85.00', '75.00');

显示最终值（na）： 

select s.nis, nama, m.kd_mp, nm_mp, kkm, (akhir) as na,
if (akhir <kkm,'GAGAL','TUNTAS') as ket from siswa s, mata_pljran m, nilai n where
s.nis=n.nis and m.kd_mp=n.kd_mp;

结果： 

+------+---------+-----------+------------------+------+---------+--------+
| nis  | nama    | kd_mp     | nm_mp            | kkm  | na      | ket    |
+------+---------+-----------+------------------+------+---------+--------+
| 0001 | budi    | 10.01.001 | matematika       |   70 | 84.7500 | TUNTAS |
| 0002 | joko    | 10.01.001 | matematika       |   70 | 79.4500 | TUNTAS |
| 0003 | santoso | 10.01.001 | matematika       |   70 | 87.2000 | TUNTAS |
| 0005 | marta   | 10.01.001 | matematika       |   70 | 84.7500 | TUNTAS |
| 0001 | budi    | 10.01.002 | bahasa indonesia |   80 | 85.0000 | TUNTAS |
| 0002 | joko    | 10.01.002 | bahasa indonesia |   80 | 83.2000 | TUNTAS |
| 0003 | santoso | 10.01.002 | bahasa indonesia |   80 | 61.8500 | GAGAL  |
| 0005 | marta   | 10.01.002 | bahasa indonesia |   80 | 85.9500 | TUNTAS |
| 0001 | budi    | 10.01.003 | kewarganegaraan  |   80 | 84.2500 | TUNTAS |
| 0002 | joko    | 10.01.003 | kewarganegaraan  |   80 | 88.7500 | TUNTAS |
| 0003 | santoso | 10.01.003 | kewarganegaraan  |   80 | 43.8000 | GAGAL  |
| 0005 | marta   | 10.01.003 | kewarganegaraan  |   80 | 90.4500 | TUNTAS |
| 0001 | budi    | 10.01.004 | agama            |   80 | 82.7500 | TUNTAS |
| 0002 | joko    | 10.01.004 | agama            |   80 | 90.9500 | TUNTAS |
| 0003 | santoso | 10.01.004 | agama            |   80 | 70.5000 | GAGAL  |
| 0005 | marta   | 10.01.004 | agama            |   80 | 76.9500 | GAGAL  |
| 0001 | budi    | 10.01.005 | bahasa inggris   |   65 | 82.0000 | TUNTAS |
| 0003 | santoso | 10.01.005 | bahasa inggris   |   65 | 86.5000 | TUNTAS |
+------+---------+-----------+------------------+------+---------+--------+

我会为nm_mp = matematika和bahasa inggris 显示 max（na）或 max（akhir） 

+------+---------+-----------+------------------+------+---------+--------+
| nis  | nama    | kd_mp     | nm_mp            | kkm  | na      | ket    |
+------+---------+-----------+------------------+------+---------+--------+
| 0003 | santoso | 10.01.001 | matematika       |   70 | 87.2000 | TUNTAS |
| 0003 | santoso | 10.01.005 | bahasa inggris   |   65 | 86.5000 | TUNTAS |
+------+---------+-----------+------------------+------+---------+--------+

我怎么能在mySQL中做到这一点？非常感谢！

我是用cmd做的，抱歉我的英文不好

修改： 由我完成^ _ ^：

select s.nis, nama, m.kd_mp, nm_mp, kkm, (akhir) as na,
if (akhir <kkm,'GAGAL','TUNTAS') as ket from siswa s, mata_pljran m, nilai n where
akhir=(select max(akhir)
from nilai as a where a.kd_mp=n.kd_mp
having nm_mp in('bahasa inggris' , 'matematika')) and
s.nis=n.nis and m.kd_mp=n.kd_mp;

结果：

+------+---------+-----------+----------------+------+-------+--------+
| nis  | nama    | kd_mp     | nm_mp          | kkm  | na    | ket    |
+------+---------+-----------+----------------+------+-------+--------+
| 0003 | santoso | 10.01.001 | matematika     |   70 | 87.20 | TUNTAS |
| 0003 | santoso | 10.01.005 | bahasa inggris |   65 | 86.50 | TUNTAS |
+------+---------+-----------+----------------+------+-------+--------+

谢谢：D

3 个答案:

答案 0 :(得分：1)

只是一个想法（实际上没有尝试过）

SELECT * FROM TABLE_NAME having max(na) = na GROUP BY nm_mp

如果它有效或无效，请告诉我。 它适用于所有类别。

对于这两个类别，试试这个。

SELECT * FROM TABLE_NAME WHERE nm_mp IN('matematika', 'bahasa inggris') having max(na) = na GROUP BY nm_mp

答案 1 :(得分：0)

试试这个： - 

 SELECT NIS, NAMA, KD_MP, NM_MP, KKM, MAX(NA), KET
 FROM YOUR_TABLE
 WHERE NM_MP = 'matematika'
 OR NM_MP = 'bahasa inggris'
 GROUP BY NM_MP

这可能对您有所帮助。

答案 2 :(得分：0)

在MySQL中，你需要使用相关子查询来做旧学校：

select *
from tab as t1
where nm_mp in ('matematika', 'bahasa inggris')
  and na = (select max(na) 
            from tab as t2
            where t1.nm_mp = t2.nm_mp)

或派生表

select t1.*
from tab as t1 join
   (select nm_mp_, max(na) as max_na 
    from tab as t2
    where nm_mp in ('matematika', 'bahasa inggris')
    group by nm_mp
   ) as t2
on t1.nm_mp = t2.nm_mp
and t1.na = t2.max_na
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