如果我在SQL Server中有两个int数据类型列,我如何编写一个查询,以便获得最大数量,在另一列的最大数量?
让我举个例子。可以说我有这张桌子:
| Name | Version | Category | Value | Number | Replication |
|:-----:|:-------:|:--------:|:-----:|:------:|:-----------:|
| File1 | 1.0 | Time | 123 | 1 | 1 |
| File1 | 1.0 | Size | 456 | 1 | 1 |
| File2 | 1.0 | Time | 312 | 1 | 1 |
| File2 | 1.0 | Size | 645 | 1 | 1 |
| File1 | 1.0 | Time | 369 | 1 | 2 |
| File1 | 1.0 | Size | 258 | 1 | 2 |
| File2 | 1.0 | Time | 741 | 1 | 2 |
| File2 | 1.0 | Size | 734 | 1 | 2 |
| File1 | 1.1 | Time | 997 | 2 | 1 |
| File1 | 1.1 | Size | 997 | 2 | 1 |
| File2 | 1.1 | Time | 438 | 2 | 1 |
| File2 | 1.1 | Size | 735 | 2 | 1 |
| File1 | 1.1 | Time | 786 | 2 | 2 |
| File1 | 1.1 | Size | 486 | 2 | 2 |
| File2 | 1.1 | Time | 379 | 2 | 2 |
| File2 | 1.1 | Size | 943 | 2 | 2 |
| File1 | 1.2 | Time | 123 | 3 | 1 |
| File1 | 1.2 | Size | 456 | 3 | 1 |
| File2 | 1.2 | Time | 312 | 3 | 1 |
| File2 | 1.2 | Size | 645 | 3 | 1 |
| File1 | 1.2 | Time | 369 | 3 | 2 |
| File1 | 1.2 | Size | 258 | 3 | 2 |
| File2 | 1.2 | Time | 741 | 3 | 2 |
| File2 | 1.2 | Size | 734 | 3 | 2 |
| File1 | 1.3 | Time | 997 | 4 | 1 |
| File1 | 1.3 | Size | 997 | 4 | 1 |
| File2 | 1.3 | Time | 438 | 4 | 1 |
| File2 | 1.3 | Size | 735 | 4 | 1 |
如何编写查询,以便选择最大Replication
值的最大Number
值?正如您所看到的,在此表中,Number中的最大值为4
,但Replication
中Number = 4
为1
的最大数量
我能想到的就是:
SELECT MAX(Replication) FROM Table
WHERE Number IS MAX;
这显然是错误的,并且不起作用。
答案 0 :(得分:1)
您可以尝试Group By
和Having
select max(Replication) from Table_Name group by [Number] having
[Number]=(select max([Number]) from Table_Name)
答案 1 :(得分:0)
只需使用子查询在where子句中查找最大数字。如果你只想要一个单一的数字作为结果,就不需要使用group by和having(这将使查询更加昂贵):
select max([replication]) from tab
where number = (select max(number) from tab)