xtable用于条件单元格格式化表的重要p值

时间:2014-07-03 12:40:21

标签: r formatting latex conditional xtable

我正在使用xtable生成放入Latex的表格,并且想知道是否有办法对单元格进行条件格式化,以便所有重要的p值都是灰色的?我在TexShop中使用Knitr。

以下是使用ggplot2中的diamonds数据并运行TukeyHSD测试从carat预测cut的示例。

library(ggplot2)
library(xtable)
summary(data.aov <- aov(carat~cut, data = diamonds))
data.hsd<-TukeyHSD(data.aov)
data.hsd.result<-data.frame(data.hsd$cut)
data.hsd.result

然后,我可以使用以下内容将data.hsd.result转换为xtable格式:

xtable(data.hsd.result)

在Latex中,输出如下:

                         diff         lwr         upr        p.adj
Good-Fair         -0.19695197 -0.23342631 -0.16047764 0.000000e+00
Very Good-Fair    -0.23975525 -0.27344709 -0.20606342 0.000000e+00
Premium-Fair      -0.15418175 -0.18762721 -0.12073628 0.000000e+00
Ideal-Fair        -0.34329965 -0.37610961 -0.31048970 0.000000e+00
Very Good-Good    -0.04280328 -0.06430194 -0.02130461 5.585171e-07
Premium-Good       0.04277023  0.02165976  0.06388070 3.256208e-07
Ideal-Good        -0.14634768 -0.16643613 -0.12625923 0.000000e+00
Premium-Very Good  0.08557350  0.06974902  0.10139799 0.000000e+00
Ideal-Very Good   -0.10354440 -0.11797729 -0.08911151 0.000000e+00
Ideal-Premium     -0.18911791 -0.20296592 -0.17526989 0.000000e+00

可以具有任何p值&lt; 0.05自动或以某种方式突出显示灰色背景?显然,对于这个集合,它将是整个列,但我希望有一些适用于我所有数据的东西。

2 个答案:

答案 0 :(得分:18)

你好试试这个:

\documentclass{article}
\usepackage{color}
\begin{document}

<<echo=FALSE, results='asis'>>=
df = data.frame(V1 = LETTERS[1:6], V2 = runif(6, 0, 1))
df$V3 = ifelse(df$V2 < 0.5, paste0("\\colorbox{red}{", df$V2, "}"), df$V2)
library(xtable)
print(xtable(df), sanitize.text.function = function(x) x)
@

\end{document}

修改

如果您有多个条件,一个解决方案是使用包dplyr和函数case_when

set.seed(123)
df <- data.frame(V1 = LETTERS[1:6], V2 = runif(6, 0, 1))

library("dplyr")
df %>% 
  mutate(
    V3 = case_when(
      V2 < 0.5 ~ paste0("\\colorbox{red}{", round(V2, 3), "}"),
      V2 >= 0.5 & V2 < 0.8 ~ paste0("\\colorbox{blue}{", round(V2, 3), "}"),
      TRUE ~ formatC(V2, digits = 3)
    )
  )
#   V1        V2                      V3
# 1  A 0.2875775  \\colorbox{red}{0.288}
# 2  B 0.7883051 \\colorbox{blue}{0.788}
# 3  C 0.4089769  \\colorbox{red}{0.409}
# 4  D 0.8830174                   0.883
# 5  E 0.9404673                    0.94
# 6  F 0.0455565  \\colorbox{red}{0.046}

答案 1 :(得分:1)

Victorp提供了一个出色的解决方案,它让我从长达数小时的奋斗中得到了解脱。然后在那天晚些时候我需要在同一个数据集上施加多个条件,这意味着我需要根据不同的条件在单元格上使用两种不同的颜色来解决这个问题,完全基于Victorp的答案,我想出了一个解决方案并希望这会有助于那些将来需要这个。

    <<echo=FALSE, results='asis'>>=
    df = data.frame(V1 = LETTERS[1:6], V2 = runif(6, 0, 1),V3 = runif(6, 0, 1))
    ## replicate the data frame of which you are going to highlight the cells
    ## the number of duplicates should be equal to number of conditions you want to impose
    temp.1<-df
    temp.2<-df
    ## impose conditions on those temporary data frame separately.
    ## change the columns you want to 
    for (i in colnames(temp.1)[2:3]) {
    temp.1[,i]= ifelse(temp.1[,i] <= 0.5,
                                paste0("\\colorbox{red}{", temp.1[,i], "}"), temp.1[,i])}
    rm(i)


    for (i in colnames(temp.2)[2]) {
    temp.2[,i]= ifelse(temp.2[,i] > 0.5 & temp.2[,i] <=0.8,
                                paste0("\\colorbox{blue}{", temp.2[,i], "}"),temp.2[,i])}
    rm(i)
    ## then record the position of cells under you conditions
    pos.1<-which(df[,] <=0.5,arr.ind = TRUE)
    pos.2<-which(df[,] >0.5 & df[,]<=0.8,arr.ind = TRUE)
    ## replace cells in original data frame that you want to highlight
    ## replace those values in temp which satisfy the condition imposed on temp.1
    if(length(pos.1)>0) {
      temp[pos.1]<-temp.1[pos.1]
    }


    ## replace those values in temp which satisfy the condition imposed on temp.2
    if(length(pos.2)>0) {
      temp[pos.2]<-temp.2[pos.2]
    }
    rm(temp.1,temp.2,pos.1,pos.2)
    @

然后按照您喜欢的方式打印df。然而,考虑到R的强大功能,我确实认为应该有更简单的方法。