我试图将d3.js画笔和谷歌地图结合起来。我有一个地图,3个按钮来控制d3画笔(实际上是我的时间轴),以及d3画笔本身。
如果我没有将地图添加到页面,按钮负责移动画笔,他们会这样做。如果我将地图添加到页面,则在启用js调试器(firebug或chrome调试器)时播放和停止功能。但是当我关闭调试器时,刷子不会重绘。它的范围将会更新(我通过alert(brush_control.extent()[0])
检查了它)但它仍然保持在行动之前(播放或停止)。
控制台中没有异常或错误。
以下是完成工作的脚本:
<script>
(function(){
var is_playing = false,
paddingLeft = 10,
paddingRight = 10,
paddingBottom = 5;
width = $(window).width() - $("#controls").width() - paddingLeft - paddingRight,
timeline_height = 100,
map_height = $(window).height() - timeline_height - paddingBottom,
my_data = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10],
brush_control = NaN;
$("#map").height(map_height);
// Remove the map below and everything works fine
var map = new google.maps.Map(d3.select("#map").node(), {
zoom: 8,
center: new google.maps.LatLng(-14.235004,-51.92528),
mapTypeId: google.maps.MapTypeId.ROADMAP
});
var timeline_svg = d3.select("#timeline").append("svg:svg")
.attr("class", "tl")
.attr("width", width)
.attr("height", timeline_height);
brush_control = d3.svg
.brush()
.x(d3.scale
.linear()
.domain([0, my_data.length])
.range([0, width])
)
.extent([0,1])
.on("brush", brush);
var brush_svg = timeline_svg.append("g")
.attr("class", "brush")
.call(brush_control)
.selectAll("rect")
.attr("height", timeline_height);
$("#playbtn")[0].addEventListener("click", play_event);
$("#pausebtn")[0].addEventListener("click", pause);
$("#stopbtn")[0].addEventListener("click", stop);
function play_event(){
if(is_playing != true){
is_playing = true;
play();
}
}
function play(){
var delay = 100;
setTimeout(function(){
var ex = brush_control.extent();
if(is_playing && ex[0 ] < my_data.length - 1){
d3.select("g").transition()
.duration(delay)
.call(brush_control.extent([ex[1], ex[1] + 1]));
ex = brush_control.extent();
play();
}
}, delay);
}
function pause(){
is_playing = false;
}
function stop(){
is_playing = false;
d3.select("g")
.transition()
.duration(1000)
.call(brush_control.extent([0, 1]))
.call(brush_control.event);
}
function brush() {
var s = d3.event.target.extent();
data_index = Math.floor(s[0]);
if (s[1]-s[0] != 1) {
d3.event.target.extent([s[0], s[0] + 1]);
d3.event.target(d3.select(this));
}
}
}());
</script>
答案 0 :(得分:1)
问题是,行d3.select("g").transition()
没有选择您期望的内容,而是谷歌地图插入代码中的内容。如果你在那里检查DOM元素,你可以找到一些插入的SVG代码:
<svg version="1.1" overflow="hidden" width="78px" height="78px" viewBox="0 0 78 78" style="position: absolute; left: 0px; top: 0px;">
<circle cx="39" cy="39" r="35" stroke-width="3" fill-opacity="0.2" fill="#f2f4f6" stroke="#f2f4f6"></circle>
<g transform="rotate(0 39 39)"><rect x="33" y="0" rx="4" ry="4" width="12" height="11" stroke="#a6a6a6" stroke-width="1" fill="#f2f4f6"></rect><polyline points="36.5,8.5 36.5,2.5 41.5,8.5 41.5,2.5" stroke-linejoin="bevel" stroke-width="1.5" fill="#f2f4f6" stroke="#000"></polyline>
</g>
</svg>
所以,将选择更改为
d3.select("g.brush").transition()
可以解决问题。