Question

我在让MSSQL与我的意图合作时遇到了一些麻烦。

检查以下内容......

重复

UseId |   Use
-------------
2254  | Primary
2255  | Primary
2256  | Primary
2257  | Intersection
2258  | Monitor
2259  | Primary
2260  | Intersection
2261  | Primary
2264  | Monitor
2269  | Secondary

唯一身份

UseID |   Use
--------------
2252  | Intersection
2253  | Monitor
2251  | Primary
2262  | Secondary

多对多表

ID   | FKey | UseId
-------------------
1    |  1   | 2251
2    |  1   | 2252
3    |  2   | 2253
4    |  2   | 2262
5    |  3   | 2254
6    |  3   | 2257
7    |  3   | 2258
8    |  4   | 2255
9    |  4   | 2260
10   |  5   | 2259
11   |  5   | 2269

我想在“多对多”表上运行更新查询，该表将与重复项和唯一标识符上的使用列匹配，然后使用匹配的唯一UseId替换“复制”多对多表中的UseIds。 ..

由此产生的良好数据看起来像这样......

好多对多......

ID   | FKey | UseId
-------------------
1    |  1   | 2251
2    |  1   | 2252
3    |  2   | 2253
4    |  2   | 2262
5    |  3   | 2251
6    |  3   | 2252
7    |  3   | 2253
8    |  4   | 2251
9    |  4   | 2262
10   |  5   | 2251
11   |  5   | 2262

感谢任何帮助

回应其中一个发布的答案......我遇到了一些困难。它似乎没有用。

更新命令正在更改“多对多”表中的记录1-4（即使它们很好）......并且不会更改任何其他记录。

此脚本提供了此问题的示例。

CREATE TABLE Uniques
(
    UseID INT,
    [Use] VARCHAR(50)
)

INSERT INTO Uniques (UseID, [Use]) VALUES (2254, 'Primary')
INSERT INTO Uniques (UseID, [Use]) VALUES (2255, 'Primary')
INSERT INTO Uniques (UseID, [Use]) VALUES (2256, 'Primary')
INSERT INTO Uniques (UseID, [Use]) VALUES (2257, 'Intersection')
INSERT INTO Uniques (UseID, [Use]) VALUES (2258, 'Monitor')
INSERT INTO Uniques (UseID, [Use]) VALUES (2259, 'Primary')
INSERT INTO Uniques (UseID, [Use]) VALUES (2260, 'Intersection')
INSERT INTO Uniques (UseID, [Use]) VALUES (2261, 'Primary')
INSERT INTO Uniques (UseID, [Use]) VALUES (2264, 'Monitor')
INSERT INTO Uniques (UseID, [Use]) VALUES (2269, 'Secondary')

CREATE TABLE Duplicates
(
    UseID INT,
    [Use] VARCHAR(50)
)

INSERT INTO Duplicates (UseID, [Use]) VALUES (2252, 'Intersection')
INSERT INTO Duplicates (UseID, [Use]) VALUES (2253, 'Monitor')
INSERT INTO Duplicates (UseID, [Use]) VALUES (2251, 'Primary')
INSERT INTO Duplicates (UseID, [Use]) VALUES (2262, 'Secondary')

CREATE TABLE ManyToMany
(
    Id INT,
    FKey INT,
    UseId INT
)

INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (1, 1, 2251)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (2, 1, 2252)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (3, 2, 2253)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (4, 2, 2262)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (5, 3, 2254)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (6, 3, 2257)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (7, 3, 2258)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (8, 4, 2255)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (9, 4, 2260)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (10, 5, 2259)
INSERT INTO ManyToMany (Id, FKey, UseId) VALUES (11, 5, 2269)

SELECT * FROM Uniques
SELECT * FROM Duplicates
SELECT * FROM ManyToMany

UPDATE  m
SET     m.UseId = u.UseId
FROM    ManyToMany m
        JOIN Duplicates d ON m.UseId = d.UseId
        JOIN Uniques u ON d.[Use] = u.[Use];

SELECT * FROM ManyToMany

DROP TABLE Uniques
DROP TABLE Duplicates
DROP TABLE ManyToMany

Answer 1

UPDATE  m
SET     m.UseId = u.UseId
FROM    ManyToMany m
        JOIN Duplicates d ON m.UseId = d.UseId
        JOIN Uniques u ON d.[Use] = u.[Use];

SQL Server Update加入两个表

1 个答案: