Question

**表输入**

(id_inpits, name, quantity_inputs)

表格输出 `（id_outputs，name_outputs，quantity_outputs，quantity_disponible）

当我想更新quantity_output并计算quantity_disponbile

时

知道：quantity_disponbile = quantity_inputs - quantity_output

我尝试过：

if(!empty($_POST['do'])) {

    $m_id = $_POST['id_output'];

    $quantity_outputs = $_POST["quantity_outputs"];

    $sql = $db->query("UPDATE outputs AS o INNER JOIN inputs As i ON i.id_input = o.inputs_id  SET o.quantity_dispo = 'select quantity_inputs from inputs - FROM (select quantity_outputs from outputs )', o.quantity_outputs = '$quantity_outputs'  WHERE o.id_output =' $m_id'"); 

    if(!$sql) {
        die(mysql_error());
    }
}

Answer 1

一个建议：quantity_disponbile应该是两个表中的计算字段。因此将逻辑拆分为两个：一个选择查询和一个更新查询。更新查询只需要更新quantity_output，选择查询可以是：

select 
  i.quantity_inputs -  o.quantity_output = quantity_disponible
from output o 
    inner join input i on i.id_inpits = o.inputs_id

我无论如何都不能纠正错字

更新内部加入两个表

1 个答案: