Question

我使用XML作为应用程序的后端......

LXML用于解析xml。

如何加密此xml文件以确保数据受到保护......

提前感谢。

Answer 1

由于XML包含重复结构，最好先compress然后encrypt。

下载并安装PyDes。

from pyDes import *
import bz2

def encrypt(data,password):
    k = des(password, CBC, "\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)
    d = k.encrypt(data)
    return d

def decrypt(data,password):
    k = des(password, CBC, "\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)
    d = k.decrypt(data)
    return d

password = "eight222" # password length should be 8

data = '''
<?xml version="1.0"?>
  <library>
   <shelf id="fiction">
    <book>
     <title>Of Mice and Men</title>
     <author>John Steinbeck</author>
    </book>
    <book>
     <title>Harry Potter and the Philosopher's Stone</title>
     <author>J.K. Rowling</author>
    </book>
   </shelf>
  </library> 
'''

print len(data)

compressed_data = bz2.compress(data)
print len(compressed_data)

encrypted_data = encrypt(compressed_data,password)

print "%r"%encrypted_data

uncompressed_encrypted_data = encrypt(data,password)

print len(encrypted_data)
print len(uncompressed_encrypted_data)
print bz2.decompress(decrypt(encrypted_data,password))

python中有很多加密库

在python中加密XML数据库

1 个答案: