Question

我有像这样的Div层

...
<style type="text/css">
<!--
#newImg {
    position:absolute;
    left:180px;
    top:99px;
    width:704px;
    height:387px;
    z-index:1;
    background-image:url(../Pictures/repbg.png);
    background-repeat:repeat;

}

-->
</style></head>

<body>

<div id="newImg" name="newImg" ></div>
...

如何旋转它？

Answer 1

您可以使用cssSandpaper来使用transform属性，该属性可用于旋转Gecko（Firefox），WebKit（Safari，Chrome），Opera甚至Internet Explorer中的元素。

Answer 2

这是一个jQuery插件，可以旋转图像：http://code.google.com/p/jquery-rotate/

Answer 3

//
// Rotate a <DIV> element
//
// - DIV position must be absolute or relative
// - Will use the center point of DIV as origin for tilt
//
// I think it will work on most browsers (including ie6, ie7 & ie8)
//
function divRotate( divObj, divTop, divLeft, divHeight, divWidth, newAngleDeg )
    {
    var radAngle = Math.PI * newAngleDeg / 180;
    var spinAngle = radAngle;

    if ( window.navigator.userAgent.indexOf ( 'MSIE ' ) <= 0 || typeof document.documentElement.style.opacity!='undefined' )
        radAngle = -radAngle;

    var sinAngle = parseFloat(parseFloat(Math.sin(radAngle)).toFixed(8));
    var cosAngle = parseFloat(parseFloat(Math.cos(radAngle)).toFixed(8));

    var m11 = cosAngle;
    var m12 = -sinAngle;
    var m21 = sinAngle;
    var m22 = cosAngle;

    if ( window.navigator.userAgent.indexOf ( 'MSIE ' ) <= 0 || typeof document.documentElement.style.opacity!='undefined' )
        {
        divObj.style.WebkitTransform = 'matrix('+ m11 +','+ m12 +','+ m21 +','+ m22 +',' + 0 + ',' + 0 + ')';
        divObj.style.MozTransform = 'matrix('+ m11 +','+ m12 +','+ m21 +','+ m22 +',' + 0 + 'px,' + 0 + 'px)';
        divObj.style.msTransform = 'matrix('+ m11 +','+ m12 +','+ m21 +','+ m22 +',' + 0 + ',' + 0 + ')';
        divObj.style.OTransform = 'matrix('+ m11 +','+ m12 +','+ m21 +','+ m22 +',' + 0 + ',' + 0 + ')';
        divObj.style.transform = 'matrix('+ m11 +','+ m12 +','+ m21 +','+ m22 +',' + 0 + ',' + 0 + ')';

        divObj.style.top = divTop + 'px';
        divObj.style.left = divLeft + 'px';

        return;
        }

    var sinSpinAngle = -parseFloat(parseFloat(Math.sin(-spinAngle)).toFixed(8));
    var cosSpinAngle = parseFloat(parseFloat(Math.cos(-spinAngle)).toFixed(8));
    var sinAnglePerp = parseFloat(parseFloat(Math.sin(radAngle-Math.PI)).toFixed(8));
    var cosAnglePerp = parseFloat(parseFloat(Math.cos(radAngle-Math.PI)).toFixed(8));
    var halfHeight = divHeight/2;
    var halfWidth = divWidth/2;
    var radius = Math.sqrt(halfHeight*halfHeight + halfWidth*halfWidth);

    var ulx = divLeft + halfWidth - radius*cosSpinAngle + sinAnglePerp*halfHeight;
    var uly = divTop + halfHeight - radius*sinSpinAngle + cosAnglePerp*halfHeight;

    var urx = radius*cosSpinAngle + divLeft + halfWidth + sinAnglePerp*halfHeight;
    var ury = radius*sinSpinAngle + divTop + halfHeight + cosAnglePerp*halfHeight;

    var lrx = radius*cosSpinAngle + divLeft + halfWidth - sinAnglePerp*halfHeight;
    var lry = radius*sinSpinAngle + divTop + halfHeight - cosAnglePerp*halfHeight;

    var llx = divLeft + halfWidth - radius*cosSpinAngle - sinAnglePerp*halfHeight;
    var lly = divTop + halfHeight - radius*sinSpinAngle - cosAnglePerp*halfHeight;

    divObj.style.filter = "filter: progid:DXImageTransform.Microsoft.Matrix( M11="+m11+", M12="+m12+", M21="+m21+", M22="+m22+", sizingMethod='auto expand' );";

    var spinTop = Math.min( uly, ury, lry, lly );
    var spinRight = Math.max( ulx, urx, lrx, llx );
    var spinBottom = Math.max( uly, ury, lry, lly );
    var spinLeft = Math.min( ulx, urx, lrx, llx );

    divObj.style.top = spinTop + 'px';
    divObj.style.right = spinRight + 'px';
    divObj.style.bottom = spinBottom + 'px';
    divObj.style.left = spinLeft + 'px';
    }

Answer 4

此时本地执行此操作的唯一方法是使用-moz-transform。

详细信息在这里。

https://developer.mozilla.org/en/CSS/-moz-transform

这是不跨浏览器兼容，因此使用风险自负。

~~更新：显然，还有一个jQuery插件可以帮到你：~~

~~http://plugins.jquery.com/project/Transform/~~

~~可能还有一点兼容性。~~

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