Question

我正在尝试按照here

编译桥接模式C ++示例代码

但是当我g++ -o Bridge Bridge.C

时，我收到编译错误

程序：

#include <iostream>
#include <iomanip>
#include <string>

class TimeImp {
  public:
    TimeImp(int hr, int min) {
        hr_ = hr;
        min_ = min;
    }
    virtual void tell() {
        cout << "time is " << setw(2) << setfill(48) << hr_ << min_ << endl; //error
    }
  protected:
    int hr_, min_;
};

class CivilianTimeImp: public TimeImp {
  public:
    CivilianTimeImp(int hr, int min, int pm): TimeImp(hr, min) {
        if (pm)
          strcpy(whichM_, " PM");
        else
          strcpy(whichM_, " AM");
    }

    /* virtual */
    void tell() {
        cout << "time is " << hr_ << ":" << min_ << whichM_ << endl;
    }
  protected:
    char whichM_[4];
};

class ZuluTimeImp: public TimeImp {
  public:
    ZuluTimeImp(int hr, int min, int zone): TimeImp(hr, min) {
        if (zone == 5)
          strcpy(zone_, " Eastern Standard Time");
        else if (zone == 6)
          strcpy(zone_, " Central Standard Time");
    }

    /* virtual */
    void tell() {
        cout << "time is " << setw(2) << setfill(48) << hr_ << min_ << zone_ << endl; //error
    }
  protected:
    char zone_[30];
};

class Time {
  public:
    Time(){}
    Time(int hr, int min) {
        imp_ = new TimeImp(hr, min);
    }
    virtual void tell() {
        imp_->tell();
    }
  protected:
    TimeImp *imp_;
};

class CivilianTime: public Time {
  public:
    CivilianTime(int hr, int min, int pm) {
        imp_ = new CivilianTimeImp(hr, min, pm);
    }
};

class ZuluTime: public Time {
  public:
    ZuluTime(int hr, int min, int zone) {
        imp_ = new ZuluTimeImp(hr, min, zone);
    }
};

int main() {
  Time *times[3];
  times[0] = new Time(14, 30);
  times[1] = new CivilianTime(2, 30, 1);
  times[2] = new ZuluTime(14, 30, 6);
  for (int i = 0; i < 3; i++)
    times[i]->tell();
}

错误：

] #g ++ -o Bridge Bridge.C Bridge.C：在成员函数'virtual void中 TimeImp :: tell（）'：Bridge.C：14：错误：不匹配'operator＆lt;＆lt;'in “的std ::运营商LT;＆LT; [_CharT = char，_Traits = std :: char_traits]（（（std :: basic_ostream＆gt;＆amp;）（（std :: basic_ostream＆gt; ）std :: operator＆lt;＆lt; [with _Traits = std :: char_traits]（（（std :: basic_ostream＆gt;＆amp;）（＆amp; std :: cout）），（（const char ）＆＃34;时间是＆＃34;）））），std :: setw（2））＆lt;＆lt; std :: setfill with _CharT = int' /usr/lib/gcc/x86_64-redhat-linux/4.1.2/../../../../include/c++/4.1.2/bits/ostream.tcc:67：注意：候选人是： std :: basic_ostream＆lt; _CharT，_Traits＆gt;＆amp; 的std :: basic_ostream＆LT; _CharT， _Traits＆gt; :: operator＆lt;＆lt;（std :: basic_ostream＆lt; _CharT，_Traits＆gt;＆amp;（）（std :: basic_ostream＆lt; _CharT，_Traits＆gt;＆amp;））[with _CharT = char， _Traits = std :: char_traits] /usr/lib/gcc/x86_64-redhat-linux/4.1.2/../../../../include/c++/4.1.2/bits/ostream.tcc： 78：注意：std :: basic_ostream＆lt; _CharT，_Traits＆gt;＆amp; std :: basic_ostream＆lt; _CharT，_Traits＆gt; :: operator＆lt;＆lt;（std :: basic_ios＆lt; _CharT， _Traits＆GT;＆安培; （）（std :: basic_ios＆lt; _CharT，_Traits＆gt;＆amp;））[with _CharT = char，_ Traits = std :: char_traits] /usr/lib/gcc/x86_64-redhat-linux/4.1.2/ ../../../../include/c++/4.1.2/bits/ostream.tcc:90:note:std :: basic_ostream＆lt; _CharT，_Traits＆gt;＆amp; std :: basic_ostream＆lt; _CharT，_Traits＆gt; :: operator＆lt;＆lt;（std :: ios_base＆amp; （*）（std :: ios_base＆amp;））[与_CharT = char，_Traits = 的std :: char_traits]

这是错误的一部分，它以相同的模式扩展。

我复制粘贴相同的代码，分析错误行但无法获得。

有人可以告诉我哪里出错了吗？

Answer 1

std::setfill takes a char，您传递int。

尝试：

cout << "time is " << setw(2) << setfill(' ') << hr_ << min_ << endl;

桥模式C ++代码编译错误

1 个答案: