这是我的代码:
import ply.lex as lex
tokens = (
'LANGLE', # <
'LANGLESLASH', # </
'RANGLE', # >
'EQUAL', # =
'STRING', # "hello"
'WORD') # Welcome!
state = (
("htmlcomment", "exclusive"),
)
t_ignore = ' '
def t_htmlcomment(token):
r'<!--'
token.lexer.begin('htmlcomment')
def t_htmlcomment_end(token):
r'-->'
token.lexer.lineno += token.value.count('\n')
token.lexer.begin('INITIAl')
def t_htmlcomment_error(token):
token.lexer.skip(1)
def t_newline(token):
r'\n'
token.lexer.lineno += 1
pass
def t_LANGLESLASH(token):
r'</'
return token
def t_LANGLE(token):
r'<'
return token
def t_RANGLE(token):
r'>'
return token
def t_EQUAL(token):
r'='
return token
def t_STRING(token):
r'"[^"]*"'
token.value = token.value[1:-1] # dropping off the double quotes
return token
def t_WORD(token):
r'[^ <>\n]+'
return token
webpage = "This is <b>my</b> webpage"
htmllexer = lex.lex()
htmllexer.input(webpage)
while True:
tok = htmllexer.token()
if not tok: break
print(tok)
当我运行它时出现错误:
Traceback (most recent call last):
File "/home/******/Documents/pro/main.py", line 62, in <module>
htmllexer = lex.lex()
File "/usr/lib/python2.7/dist-packages/ply/lex.py", line 901, in lex
raise SyntaxError("Can't build lexer")
SyntaxError: Can't build lexer
我认为问题在于:
state = (
("htmlcomment", "exclusive"),
)
但是我无法解决它。
有没有人有任何建议我该如何解决?
感谢您的帮助!