Question

[{
    "circlemarker": [{
        "type": "circle_marker"
    }, {
        "latlong": "abc"
    }]
}, {
    "connector_marker": [{
        "type": "icon_marker"
    }, {
        "latlong": "pqr"
    }]
}, {
    "icon_marker": [{
        "type": "connector_marker"
    }, {
        "latlong": "xyz"
    }]
}]

我想访问每个标记的latlong值。那么如何才能访问此结构中的每个属性。

Answer 1

您可以获取latlong数据：

for (var a = 0; a < obj.length; a++) {
    var key = Object.keys(obj[a])[0];
    var latlong = obj[a][key][1];
    console.log(latlong));
}

但我认为数据结构不正确，这是更好的解决方案：

var markers = [{
    "name": "circlemarker",
    "type": "circle_marker"
    "latlong": "abc"
}, {
    "name": "connector_marker",
    "type": "icon_marker",
    "latlong": "pqr"
}, {
    "name": "icon_marker",
    "type": "connector_marker",
    "latlong": "xyz"
}];

Answer 2

我认为这应该适合你： -

var makers = [{"circlemarker":[{"type":"circle_marker"},{"latlong":"abc"}]},{"connector_marker":[{"type":"icon_marker"},{"latlong":"pqr"}]},{"icon_marker":[{"type":"connector_marker"},{"latlong":"xyz"}]}];
makers.forEach(function(maker){
    var makerName = Object.keys(maker)[0];
    console.log(maker[makerName][1]["latlong"]);
});

Answer 3

因此，对于数组中的每个对象，您希望从第一个键中提取latlong，该键也引用另一个对象数组。我会修复这个数据结构，但如果你无法控制它，你可以这样做：

#!/usr/bin/env node

var data = [{
    "circlemarker": [{
        "type": "circle_marker"
    }, {
        "latlong": "abc"
    }]
}, {
    "connector_marker": [{
        "type": "icon_marker"
    }, {
        "latlong": "pqr"
    }]
}, {
    "icon_marker": [{
        "type": "connector_marker"
    }, {
        "latlong": "xyz"
    }]
}];

var _ = require('lodash')
, coords = [];

_.each(data, function(item){
  //console.log(item);

  var key = _(Object.keys(item)).first()
    , first = item[key]
    , latLong = _.pluck(first, 'latlong')[1];

  if ( latLong ) {
     coords.push(latLong);
  }

});

console.log(coords);

产生以下输出：

[ 'abc', 'pqr', 'xyz' ]

如何从javascript中的对象数组中检索属性值

3 个答案: