我正在尝试创建一个简单的“库存”系统,该系统存储项目的项目名称,并将剩余的信息存储为值。但是,我很难弄清楚如何阅读信息。例如,如果我说了10个项目的列表,并且我想从下面列出的关键“电视”中选择项目“类型”信息,我该怎么做?
电视{大,5,3,假,动态,0.8,20}
Hashtable myItems = new Hashtable();
protected virtual bool OnAttempt_AddItem(object args) {
object[] arr = (object[])args;
string ItemType = (string)arr[0];
string ItemName = (string)arr[1];
int ItemAmount = (arr.Length == 2) ? (int)arr[2] : 1;
int ItemACanHave = (arr.Length == 3) ? (int)arr[3] : 1;
bool ItemClear = (bool)arr[4];
string ItemEffect = (string)arr[5];
float ItemModifier = (float)arr[6];
int ItemWeight = (int)arr[7];
// enforce ability to have atleast 1 item of each type
ItemACanHave = Mathf.Max(1, ItemACanHave);
myItems[ItemName] = new object[] {ItemType, ItemAmount, ItemACanHave, ItemClear, ItemEffect, ItemModifier, ItemWeight };
return true;
}
答案 0 :(得分:1)
创建一个项目类来封装属性:
public class InventoryItem
{
public string Name;
public string Type;
public int Amount;
public int CanHave; // you should consider renaming this - it's very unclear what this could mean
public bool Clear;
public string Effect;
public float Modifier;
public int Weight;
}
然后您可以使用词典来存储项目:
Dictionary<string, InventoryItem> inventory = new Dictionary<string, InventoryItem>();
inventory["television"] = new InventoryItem
{
Name = "television", Type = "large", Amount = 5,
CanHave = 3, Clear = false, Effect = "dynamic",
Modifier = 0.8, Weight = 20
});
你可以这样查看:
Console.WriteLine("Type of television is: ", inventory["television"].Type);
答案 1 :(得分:1)
我建议你考虑清单列表中某种类型的多个项目的可能性,即两个或更多电视机而不是一个。
使用基类和派生类:
public class InventoryItem
{
public string ItemType { get; set; }
public string ItemName { get; set; }
public int ItemAmount { get; set; }
public int ItemACanHave { get; set; }
public bool ItemClear { get; set; }
public string ItemEffect { get; set; }
public float ItemModifier { get; set; }
public int ItemWeight { get; set; }
}
public class Radio : InventoryItem
{
}
public class Television : InventoryItem
{
}
// TODO: add your derived classes
使用List<InventoryItem>
存储集合:
List<InventoryItem> InventoryItems = new List<InventoryItem>();
修改你的方法(不要忘记添加异常处理,因为有时你可能得到的输入与你在args
对象中所期望的输入不同):
protected virtual bool OnAttempt_AddItem(object args)
{
// TODO: handle unboxing exceptions, size of the array etc
//
try
{
object[] arr = (object[])args;
switch (arr[0].ToString().ToLower())
{
// TODO: add other types (Radio etc)
case "television":
var tv = new Television();
tv.ItemType = (string)arr[0];
tv.ItemName = (string)arr[1];
tv.ItemAmount = (arr.Length == 2) ? (int)arr[2] : 1;
tv.ItemACanHave = (arr.Length == 3) ? (int)arr[3] : 1;
tv.ItemClear = (bool)arr[4];
tv.ItemEffect = (string)arr[5];
tv.ItemModifier = (float)arr[6];
tv.ItemWeight = (int)arr[7];
// enforce ability to have atleast 1 item of each type
tv.ItemACanHave = Math.Max(1, tv.ItemACanHave);
InventoryItems.Add(tv);
break;
default:
var genericItem = new InventoryItem();
genericItem.ItemType = (string)arr[0];
genericItem.ItemName = (string)arr[1];
genericItem.ItemAmount = (arr.Length == 2) ? (int)arr[2] : 1;
genericItem.ItemACanHave = (arr.Length == 3) ? (int)arr[3] : 1;
genericItem.ItemClear = (bool)arr[4];
genericItem.ItemEffect = (string)arr[5];
genericItem.ItemModifier = (float)arr[6];
genericItem.ItemWeight = (int)arr[7];
// enforce ability to have atleast 1 item of each type
genericItem.ItemACanHave = Math.Max(1, genericItem.ItemACanHave);
InventoryItems.Add(genericItem);
break;
//handle other cases
}
return true;
}
catch (Exception ex)
{
// log the error
return false;
}
}
检索过滤后的项目如下:
var largeTvType = inventory.InventoryItems.OfType<Television>()
// filter by type (or other criteria)
.Where(tv => tv.ItemType == "large")
// select only the property your interested in (in the case below
// it will be always "television" because that's part of the
// logic inside the OnAttempt_AddItem method's switch statement)
.Select(tv => tv.ItemType);
然而,正如ChrisWue在答案中建议的那样,如果您知道您的广告资源列表会非常大,我建议您使用Dictionary<string, InventoryItem>
,string
密钥是唯一的广告资源标识符。它会更快。