我有3张桌子。
table_main:
+-----+----------+-------------+
| _id | ENTRY_ID | DATA |
+-----+----------+-------------+
| 1 | a1 | some data 1 |
| 2 | a2 | some data 2 |
| 3 | a3 | some data 3 |
+-----+----------+-------------+
table_additions:
+----------+-----------+
| ENTRY_ID | TIMESTAMP |
+----------+-----------+
| a1 | 123456 |
| a2 | 123458 |
| a1 | 123654 |
| a1 | 123658 |
| a2 | 123843 |
| a3 | 123911 |
+----------+-----------+
table_deletions:
+----------+-----------+
| ENTRY_ID | TIMESTAMP |
+----------+-----------+
| a3 | 123556 |
| a2 | 123558 |
| a3 | 123754 |
| a1 | 123858 |
| a3 | 123863 |
| a3 | 123976 |
+----------+-----------+
我在android工作。我想从table_main
获取所有条目的数据:
table_additions
>中出现的次数发生的人数table_deletions
因此,在上面的例子中,输出应该是:
+-----+----------+-------------+
| _id | ENTRY_ID | DATA |
+-----+----------+-------------+
| 1 | a1 | some data 1 |
| 2 | a2 | some data 2 |
+-----+----------+-------------+
答案 0 :(得分:0)
这可以通过相关子查询来完成:
SELECT *
FROM table_main
WHERE (SELECT COUNT(*)
FROM table_additions
WHERE entry_id = table_main.entry_id
) >
(SELECT COUNT(*)
FROM table_deletions
WHERE entry_id = table_main.entry_id
)