Question

我对SQL / MySQL和Stackoverflow很新，我试图通过 iReport 创建一个查询（虽然我不必使用 iReport < / em>） SugarCRM CE 。我需要的是创建一个报告，显示链接到特定“用户”（员工）的“推荐”，“语音邮件”，“电子邮件”和“Call_ins”的数量。我目前设置的查询工作;但它会多次运行数据，生成200多页的报告。这是我目前使用的代码：

SELECT ( SELECT COUNT(*) FROM `leads` INNER JOIN `leads_cstm` ON `leads`.`id` = `leads_cstm`.`id_c` WHERE (leadtype_c = 'Referral' AND users.`id` = leads.`assigned_user_id`) ), ( SELECT COUNT(*) FROM `leads` INNER JOIN `leads_cstm` ON `leads`.`id` = `leads_cstm`.`id_c` WHERE (leadtype_c = 'VM' AND users.`id` = leads.`assigned_user_id`) ), ( SELECT COUNT(*) FROM `leads` INNER JOIN `leads_cstm` ON `leads`.`id` = `leads_cstm`.`id_c` WHERE (leadtype_c = 'Email' AND users.`id` = leads.`assigned_user_id`) ), users.`first_name`,users.`last_name` FROM `users` users, `leads` leads

我很感激任何指导！

Answer 1

您想使用条件求和。以下使用MySQL语法：

SELECT sum(leadtype_c = 'Referral') as Referrals,
       sum(leadtype_c = 'VM') as VMs,
       sum(leadtype_c = 'Email') as Emails,
       users.`first_name`, users.`last_name`
FROM users join
    `leads`
     on  users.`id` = leads.`assigned_user_id` INNER JOIN
     `leads_cstm`
     ON `leads`.`id` = `leads_cstm`.`id_c`
group by users.id;

Answer 2

您可以将COUNT与CASE一起使用：

SELECT u.first_name, 
    u.last_name, 
    count(case when leadtype_c = 'Referral' then 1 end),
    count(case when leadtype_c = 'VM' then 1 end),
    count(case when leadtype_c = 'Email' then 1 end)
FROM users u
    JOIN leads l ON u.id = l.assigned_user_id
    JOIN leads_cstm lc ON l.id = lc.id_c
GROUP BY u.id

要匹配您的确切结果，您应该使用OUTER JOIN，但这可以让您了解。

A Visual Explanation of SQL Joins

根据用户ID计算出现次数

2 个答案: