我的项目中有三个用c ++编写的函数。它们位于相同的.cpp文件中,我有两个头文件。
现在,我有三个相应的线程,这样,第二个线程从第一个线程获取输出,最后一个线程等待,直到第二个线程结束其操作。注意线程在"永远环路"即while(1){....}
source.cpp看起来像这样:
#include <iostream>
#include "source.h"
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
void source::first_function(int size)
{
for(int i=0;i<size;i++)
{
container.push_back(i);//container is global variable vector of type int declared in glob_variables.h
}
}
//~~~~~~~~~~~~~~~~~~~~~~
void source::second_function()
{
//sleep until the first function fills the the vector to set set its size to matrix.n_rows
matrix.set_size(container.size(),33);
for(int i=0;i<container.size();i++)
{
for(int j=0;j<50;j++)
{
matrix(i,j)=i+j;//matrix is also a global variable in glob_variables.h
}
}
}
//~~~~~~~~~~~~~~~~~~~~~~
void source::third_function()
{
//sleep untill the second function fills the matrix, then print
cout<<matrix;//print out the matrix
}
source.h:
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
class source
{
public:
void first_function(int size);
void second_function();
void third_function();
};
glob_variables.h:
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
extern mat matrix;
extern vector<int> container;
Main.cpp的:
#include <iostream>
#include <stdio.h>
#include <pthread.h>
#include "source.h"
#include "glob_variables.h"
#include "armadillo"
#include <vector>
using namespace arma;
using namespace std;
//thread functions
void* first_reader(void* id1)
{
source mysource;
while(1)
{
mysource.first_function(80);
}
}
void* second_reader(void* id2)
{
source mysource;
while(1)
{
mysource.second_function();
}
}
void* third_reader(void* id3)
{
source mysource;
while(1)
{
mysource.third_function();
}
}
int main()
{
pthread_t first;
pthread_t second;
pthread_t third;
int hndl_first;
int hndl_second;
int hndl_third;
hndl_first = pthread_create(&first, NULL, first_reader, NULL);
hndl_second= pthread_create(&second, NULL, second_thread, NULL);
hndl_third;= pthread_create(&third, NULL,third_thread, NULL);
pthread_exit(NULL);
return 0;
}
我可以使用任何技术来完成此操作或任何简单示例。感谢。
答案 0 :(得分:0)
尝试使用以下链接。 AutoResetEvent满足您的要求。链接中的代码正是您所期望的。
答案 1 :(得分:0)
我想你想顺序玩线程。 在第一个帖子做一些事情 - &gt;在第二个主题中做一些事情 - &gt;在第三线程中做点什么。
是不是? 在这种情况下,您可以使用信号。
示例:
pthread_cond_t cond;
pthread_mutex_t mtx;
typedef enum {
ready1,
ready2,
ready3
} thread_ready;
thread_ready t_ready;
void* first_reader(void* id1)
{
//source mysource;
while(1)
{
pthread_mutex_lock(&mtx);
while(t_ready != ready1)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "first" << std::endl;
//mysource.first_function(80);
pthread_mutex_lock(&mtx);
t_ready = ready2;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
}
}
void* second_reader(void* id2)
{
//source mysource;
while(1)
{
pthread_mutex_lock(&mtx);
while(t_ready != ready2)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "second" << std::endl;
//mysource.second_function();
pthread_mutex_lock(&mtx);
t_ready = ready3;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
}
}
void* third_reader(void* id3)
{
//source mysource;
while(1)
{
pthread_mutex_lock(&mtx);
while(t_ready != ready3)
pthread_cond_wait(&cond, &mtx);
pthread_mutex_unlock(&mtx);
std::cout << "third" << std::endl;
//mysource.third_function();
pthread_mutex_lock(&mtx);
t_ready = ready1;
pthread_cond_signal(&cond);
pthread_mutex_unlock(&mtx);
sleep(1);
}
}
int main()
{
pthread_t first;
pthread_t second;
pthread_t third;
int hndl_first;
int hndl_second;
int hndl_third;
pthread_cond_init(&cond,NULL);
pthread_mutex_init(&mtx,NULL);
t_ready = ready1;
hndl_first = pthread_create(&first, NULL, first_reader, NULL);
hndl_second = pthread_create(&second, NULL, second_reader, NULL);
hndl_third = pthread_create(&third, NULL,third_reader, NULL);
pthread_join(first, NULL);
pthread_join(second, NULL);
pthread_join(third, NULL);
return 0;
}
实际上这个案子不需要制作3个帖子。如果你想要我的代码,你最好只做一个帖子。