Question

我有这个代码可以全局监听键盘消息：

#include <stdio.h>
#include <iostream>
#include <cstdlib>
#include <unistd.h>
#include <X11/Xlib.h>
#include <time.h>

using namespace std;


char keymap[32];
char prevKeymap[32];

bool hasTyped(Display* display)
{
    XQueryKeymap(display, keymap);
    for(int i=0; i<32; i++)
    {
        if (prevKeymap[i]!=keymap[i])
        {
            XQueryKeymap(display, prevKeymap);
            return true;
        }
    }
    return false;
}

int main(int , char *[])
{
    //setBrightness(defaultBrightness);
    Display *display;
    Window root, fromroot, tmpwin;
    int x, y,prev_x,prev_y, tmp;
    uint tmp2;

    if ((display = XOpenDisplay(NULL)) == NULL)
    {
        fprintf(stderr, "xpointerswap: fatal: cannot open local X display\n");
        exit(100);
    }

    root = DefaultRootWindow(display);

    XQueryPointer(display, root, &fromroot, &tmpwin, &prev_x, &prev_y, &tmp, &tmp, &tmp2);
    XQueryKeymap(display, prevKeymap);

    while(1)
    {
        XQueryPointer(display, root, &fromroot, &tmpwin, &x, &y, &tmp, &tmp, &tmp2);
        if(x!=prev_x || y!=prev_y || hasTyped(display))
        {
            prev_x = x;
            prev_y = y;
            cout<< "(" << x << "," <<  y << ")\n";
        }
    }
    return EXIT_SUCCESS;
}

（reference）

它会侦听键盘消息，但是当按下某个键时，它会键入鼠标指针的位置（我希望它代替打印键码）。如何更改它以便打印键码（当按下某个键时）？

全局捕获（监听）鼠标和键盘而不在X11中消耗

0 个答案: