Question

这是我连接数据库的类，它有一个循环查看结果的查询方法，但它给了我这个错误：

致命错误：第30行的C：\ Apache24 \ htdocs \ classes \ DB.php中的Call to undefined method mysqli::fetch_assoc()

我知道问题出在我的query（）方法中，我尝试使用非静态属性，但错误仍在继续。

<?php

    class DB {
        private static $db_name = "data_db";
        private static $db_user = "root";
        private static $db_pass = "root";
        private static $db_host = "localhost";

        private static $row;
        private static $instance = null;

        public static function get_instance() {
            if(!isset(self::$instance))
                self::$instance = new self;

            return self::$instance;
        }

        //returns mysqli object.
        private function __construct() {
            $this->mysqli = new mysqli(self::$db_host, self::$db_user, self::$db_pass, self::$db_name);
        }

        public function __destruct() {
            $this->mysqli->close();
        }

        public function query($query) {
        if ($result = $this->mysqli->query($query)) {
            if($result->num_rows > 1) {
                $rows = array();            
                while ($item = $result->fetch_assoc()) {
                    $rows[] = $item;
                }
            } else {
                $rows = $result->fetch_assoc();
            }

                return $rows;
        }
    }

        /**
         * Private clone method to prevent cloning of the instance of the
         * *Singleton* instance.
         *
         * @return void
         */
        private function __clone() {}

        /**
         * Private unserialize method to prevent unserializing of the *Singleton*
         * instance.
         *
         * @return void
         */
        private function __wakeup() {}

    }
?>

Answer 1

MySQLi对象没有方法fetch_assoc。您必须使用查询结果。例如：

public function query($query) {
    $result = $this->mysqli->query($query);

    $rows = array();
    while ($item = $result->fetch_assoc()) {
        $rows[] = $item;
    }

    return $items;
}

使用mysqli fetch assoc（）获取mysqli结果时出错

1 个答案: