Question

我在php / mysqli代码中收到一个致命错误，该错误表明第46行：

Fatal error: Call to undefined method mysqli_stmt::fetch_assoc() in ...

我只是想知道如何删除这个致命错误？

它指向的代码行在这里：

$row = $stmt->fetch_assoc();

原始代码：

$query = "SELECT Username, Email FROM User WHERE User = ?";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s",$user);
// execute query
$stmt->execute(); 
// get result and assign variables (prefix with db)
$stmt->bind_result($dbUser, $dbEmail);
//get number of rows
$stmt->store_result();
$numrows = $stmt->num_rows();                                      

if ($numrows == 1){

$row = $stmt->fetch_assoc();
$dbemail = $row['Email'];

}

更新代码：

$query = "SELECT Username, Email FROM User WHERE User = ?";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s",$user);
// execute query
$stmt->execute(); 
// get result and assign variables (prefix with db)
$stmt->bind_result($dbUser, $dbEmail);
//get number of rows
$stmt->store_result();
$numrows = $stmt->num_rows();                                      

if ($numrows == 1){    
  $row = $stmt->fetch_assoc();
  $dbemail = $row['Email'];    
}

Answer 1

变量$ stmt的类型为mysqli_stmt，而不是mysqli_result。 mysqli_stmt类没有为其定义的方法“fetch_assoc（）”。

您可以通过调用其get_result（）方法从mysqli_stmt对象中获取mysqli_result对象。 为此您需要安装mysqlInd驱动程序！

$result = $stmt->get_result();
row = $result->fetch_assoc();

如果您没有安装驱动程序，可以像这样获取结果：

$stmt->bind_result($dbUser, $dbEmail);
while ($stmt->fetch()) {
    printf("%s %s\n", $dbUser, $dbEmail);
}

所以你的代码应该成为：

$query = "SELECT Username, Email FROM User WHERE User = ?";
// prepare query
$stmt=$mysqli->prepare($query);
// You only need to call bind_param once
$stmt->bind_param("s",$user);
// execute query
$stmt->execute(); 
// bind variables to result
$stmt->bind_result($dbUser, $dbEmail);
//fetch the first result row, this pumps the result values in the bound variables
if($stmt->fetch()){
    echo 'result is ' . dbEmail;
}

Answer 2

改变，

$stmt->store_result();

到

$result = $stmt->store_result();

和

更改，

$row = $stmt->fetch_assoc();

到

$row = $result->fetch_assoc();

Answer 3

你错过了这一步

$stmt = $mysqli->prepare("SELECT id, label FROM test WHERE id = 1");
$stmt->execute();
$res = $stmt->get_result(); // you have missed this step
$row = $res->fetch_assoc();

Answer 4

我意识到这段代码是在stackoverflow上的某个地方提供的：

//get number of rows
$stmt->store_result();
$numrows = $stmt->num_rows();

我试过它来获取行数，但意识到我不需要行$stmt->store_result();，而且它没有得到我的号码。我用过这个：

$result      = $stmt->get_result();
$num_of_rows = $result->num_rows;
......
$row         = $result->fetch_assoc();
$sample      = $row['sample'];

Answer 5

Asciiom指出，最好使用mysqlnd。但是，如果您处于一种不允许安装mysqlnd的奇怪情况，那么仍然可以将数据放入没有它的关联数组中。尝试使用此答案中的代码 Mysqli - Bind results to an Array

如何在获取关联数组时删除致命错误

5 个答案: