我有一个包含多行数据的表格，如下所示：
16 W:\2-Work\ALBO\00_Proposal\ALxO_Amendement #1_20091022_signed.pdf
17 W:\2-Work\ALBO\00_Proposal\Level1\ALBO_Amendment #1_20110418.docx
18 W:\2-Work\ALBO\00_Proposal\A\BR\T\X_#1_20110418_final.docx
19 W:\2-Work\ALBO\MyOptionl\AO_Amendment_2 August 2013.docx
我创建了从Col1到Col10
我想用分隔符'\'
我们的想法是每栏都有：
Col1 | Col2 | Col3 | Col4 | Col5 |etc...
W: 2-Work ALBO 00_Proposal ALxO_Amendement #1_20091022_signed.pdf
我知道如何使用charindex和substring，但每行（8500行）的'\'数量不同。
你能帮帮我吗？
我正在使用Microsoft SQL Server 2012。
非常感谢
编辑2014/06/24
我的目标是生成完整路径和分割路径的XML。
实际上，这是我的想法：
1 - 识别临时表中的所有ID以进行循环
- 关于déclareune table tempo 声明@IdTable表（ id int， src nvarchar（max））
- 在injecte tous les id existant de la table 插入@IdTable（id，src） 从albo中选择id，src
- 关于déclarel'iddedébuten commencant par le plus petit 声明@id int =（从ALBO中选择min（id））
- 继续la boucle的Tnat qu'il reste des ID 而@id不为空 开始
打印@id 从@IdTable中选择@id = min（id），其中ID＆gt; @ID 结束 --Fin de la boucle des ID
2 - 拆分每一行并更新列（Colx =＆gt;之前已创建Clolumns） 这段代码应该放在我之前的循环中。
声明@products varchar（max）='W：\ 2-Work \ ALBO \ 13_WP报告\ 13_07_Monthly报告\ 13_07_01 Archives \ 2012 \ 201211 \ Draft \ ALBO-MR-201211 \ gp_scripts \ v1 \ Top10_duree_final.txt' 声明@individual varchar（max）= null
WHILE LEN（@products）＆gt; 0 开始 IF PATINDEX（'％\％'，@ products）＆gt; 0 开始 SET @individual = SUBSTRING（@ product，0，PATINDEX（'％\％'，@ products）） 选择@individual --i必须使用ID
进行更新 SET @products = SUBSTRING(@products, LEN(@individual + '\') + 1,
LEN(@products))
END
ELSE
BEGIN
SET @individual = @products
SET @products = NULL
print @individual
END
END
答案 0 :(得分：0)
以下查询将获得您要查找的内容;正如其他人所说，这不是一个特别好的设计。例如，当您查找文件名时，会发生什么？每次都在不同的列中？
无论如何，这将满足您的要求（甚至可能是您想要的）：
-- Test Data
CREATE TABLE #FilePath (FileNumber INT IDENTITY(1,1), FilePath VARCHAR(1000))
INSERT INTO #FilePath (FilePath)
SELECT 'W:\2-Work\ALBO\00_Proposal\ALxO_Amendement #1_20091022_signed.pdf' UNION
SELECT 'W:\2-Work\ALBO\00_Proposal\Level1\ALBO_Amendment #1_20110418.docx' UNION
SELECT 'W:\2-Work\ALBO\00_Proposal\A\BR\T\X_#1_20110418_final.docx' UNION
SELECT 'W:\2-Work\ALBO\MyOptionl\AO_Amendment_2 August 2013.docx'
GO
-- Numbers CTE
WITH Numbers AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM Numbers
WHERE n+1 <= 1000 -- set this to the maximum length of your file path
)
SELECT
FilePath,
[1] AS Col1,
[2] AS Col2,
[3] AS Col3,
[4] AS Col4,
[5] AS Col5,
[6] AS Col6,
[7] AS Col7,
[8] AS Col8,
[9] AS Col9,
[10] AS Col10
FROM
(
SELECT
FilePath,
ROW_NUMBER() OVER (PARTITION BY FilePath ORDER BY n) RowNum,
CAST(LTRIM(RTRIM(NULLIF(SUBSTRING('\' + FilePath + '\' , n , CHARINDEX('\' , '\' + FilePath + '\' , n) - n) , ''))) AS VARCHAR(1000)) FolderName
FROM Numbers, #FilePath
WHERE
n <= Len('\' + FilePath + '\') AND SubString('\' + FilePath + '\' , n - 1, 1) = '\' AND
CharIndex('\' , '\' + FilePath+ '\' , n) - n > 0
)P
PIVOT
(MAX(FolderName) FOR RowNum IN
([1],[2],[3],[4],[5],[6],[7],[8],[9],[10])
) UP
OPTION (MAXRECURSION 1000)-- set this to the maximum length of your file path
-- Clean up
DROP TABLE #FilePath
答案 1 :(得分：0)
正如其他人所说，这可能不是最好的做事方式，如果你解释一下你对结果做了什么，它可能会帮助我们提供更好的选择
[另外，由于某种原因，下面代码的颜色显示为奇数，因此将其复制并粘贴到您的Sql server中以便更好地查看]
drop table #Path
create table #Path (item bigint,location varchar(1000))
insert into #Path
select 16 ,'W:\2-Work\ALBO\00_Proposal\ALxO_Amendement #1_20091022_signed.pdf' union
select 17 ,'W:\2-Work\ALBO\00_Proposal\Level1\ALBO_Amendment #1_20110418.docx' union
select 18 ,'W:\2-Work\ALBO\00_Proposal\A\BR\T\X_#1_20110418_final.docx' union
select 19 ,'W:\2-Work\ALBO\MyOptionl\AO_Amendment_2 August 2013.docx'
select * from #Path;
with Path_Expanded(item,subitem,location, start, ending, split)
as(
select item
, 1 --subitem begins at 1
, location -- full location path
, 0 --start searching the file from the 0 position
, charindex('\',location) -- find the 1st '\' charactor
, substring(location,0,charindex('\',location)) --return the string from the start position, 0, to the 1st '\' charactor
from #Path
union all
select item
, subitem+1 --add 1 to subitem
, location -- full location path
, ending+1 -- start searching the file from the position after the last '\' charactor
, charindex('\',location,ending+1)-- find the 1st '\' charactor that occurs after the last '\' charactor found
, case when charindex('\',location,ending+1) = 0 then substring(location,ending+1,1000) --if you cant find anymore '\', return everything else after the last '\'
else substring(location,ending+1, case when charindex('\',location,ending+1)-(ending+1) <= 0 then 0
else charindex('\',location,ending+1)-(ending+1) end )--returns the string between the last '\' charactor and the next '\' charactor
end
from Path_Expanded
where ending > 0 --stop once you can't find anymore '\' charactors
)
--pivots the results
select item
, max(case when subitem = 1 then split else '' end) as col1
, max(case when subitem = 2 then split else '' end) as col2
, max(case when subitem = 3 then split else '' end) as col3
, max(case when subitem = 4 then split else '' end) as col4
, max(case when subitem = 5 then split else '' end) as col5
, max(case when subitem = 6 then split else '' end) as col6
, max(case when subitem = 7 then split else '' end) as col7
, max(case when subitem = 8 then split else '' end) as col8
, max(case when subitem = 9 then split else '' end) as col9
, max(case when subitem = 10 then split else '' end) as col10
from Path_Expanded
group by item
您可能更喜欢将每个文件夹放在自己的行上，如果是这样，请使用以下查询替换上面的数据透视部分
select item
, subitem
, location
, split from Path_Expanded where item = 16
答案 2 :(得分：0)
单向（去骗）：
;with T(ordinal, path, starts, pos) as (
select 1, path, 1, charindex('\', path) from #tbl
union all
select ordinal + 1, path, pos + 1, charindex('\', path, pos + 1)
from t where pos > 0
)
select [1],[2],[3],[4],[5],[6],[7],[8],[9],[10] from (
select
ordinal, path, substring(path, starts, case when pos > 0 then pos - starts else len(path) end) token
from T
) T2
pivot (max(token) for ordinal in ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10])) T3