Question

这是我的表[Property]:

Loanno  Balance amount  PropertyType
-------------------------------------
1001045 308731.770000     1
1001045 2007700.740000    2
1001045 3087318905.770    3
1001045 308731.770000     4
1001046 306589.67         1
1001046 456321.23         1
1001046 6932542.89        1
1001047 965421.34         Null
1001047 965421.34         2
1001048 567894.34         1
1001048 567894.34         2

我必须获得[Loanno]最高balance amount的属性类型。如果最高balance amount中存在平局且Property type的{{1}}与loannumber不同，那么Loan number我必须将property type填充为＆＃ 39; 8＆＃39 ;.所以我的最终输出应该如下所示：

Loanno  PropertyType
---------------------
1001045     3
1001046     1
1001047     1
1001048     8

这是我试过的查询。这是@Gord建议的。

SELECT DISTINCT 
    [Property].Loanno, 
    IIf(Loanno_MaxBalance_Count.RowCount>1, 8, [Property].PropertyType) AS PropertyType
FROM 
    [Property]
    INNER JOIN 
    (
        SELECT 
            [Property].Loanno, 
            [Property].[Balance amount], 
            COUNT(*) AS RowCount 
        FROM 
            [Property]
            INNER JOIN
            (
                SELECT 
                    Loanno, 
                    MAX([Balance amount]) AS MaxBalance 
                FROM [Property] 
                GROUP BY Loanno
            ) AS Loanno_MaxBalance
                ON Loanno_MaxBalance.Loanno=[Property].Loanno 
                    AND Loanno_MaxBalance.MaxBalance=[Property].[Balance amount]
        GROUP BY [Property].Loanno, [Property].[Balance amount]
    ) AS Loanno_MaxBalance_Count
        ON [Property].Loanno=Loanno_MaxBalance_Count.Loanno 
            AND [Property].[Balance amount]=Loanno_MaxBalance_Count.[Balance amount]

但问题出在Loan no 1001047 ，最高Balance amount 965421.34 的Property type为 1 和 NULL 。因此，对于此，上述查询将property type作为 8 返回。相反，我希望它为1.一般情况下，如果balance amount不同，Property type最高，如果它不为空，我想 8 。否则property type应为非NULL值。任何有关这方面的帮助将不胜感激。

Answer 1

这样做你想要的吗？

select LoanNo,
       iif(min(PropertyType) = max(PropertyType), min(PropertyType), 8) as PropertyType
from property as p inner join
     (select LoanNo, max(BalanceAmount) as maxba
      from property
      group by LoanNo
     ) as pmax
     on p.LoanNo = pmax.LoanNo and p.BalanceAMount = pmax.maxba
group by LoanNo;

查询以基于另一列的最大值填充MS Access中的列

1 个答案: