NodeJS中的错误是什么

时间:2014-06-22 02:40:13

标签: javascript node.js openshift

我在NodeJS 0.10中的应用程序正在我的Node localhost(127.0.0.1)中运行而我的链接不听,而且还有Discovery OpenShift!但是没有运行我的脚本,错误:(http://nodejs2-agenciadreamup.rhcloud.com/),我的GitHub(https://github.com/AlanPS/StreamBrasil)...帮助我!!!

我的代码:

var http = require('http'),
  fs = require('fs'),
  util = require('util');

http.createServer(function (req, res) {
  var path = __dirname + '/aula.mp4';
  var stat = fs.statSync(path);
  var total = stat.size;
  if (req.headers['range']) {
    var range = req.headers.range;
    var parts = range.replace(/bytes=/, "").split("-");
    var partialstart = parts[0];
    var partialend = parts[1];

    var start = parseInt(partialstart, 10);
    var end = partialend ? parseInt(partialend, 10) : total-1;
    var chunksize = (end-start)+1;
    console.log('RANGE: ' + start + ' - ' + end + ' = ' + chunksize);

    var file = fs.createReadStream(path, {start: start, end: end});
    res.writeHead(206, { 'Content-Range': 'bytes ' + start + '-' + end + '/' + total, 'Accept-Ranges': 'bytes', 'Content-Length': chunksize, 'Content-Type': 'video/mp4' });
    file.pipe(res);
  } else {
    console.log('ALL: ' + total);
    res.writeHead(200, { 'Content-Length': total, 'Content-Type': 'video/mp4' });
    fs.createReadStream(path).pipe(res);
  }
}).listen(8080, "127.0.0.1");
console.log('Server running at 127.0.0.1:8080');

2 个答案:

答案 0 :(得分:0)

看起来服务器正在使用127.0.0.1:8080,而openhift则不然。这是改变:

var http = require('http'),
  fs = require('fs'),
  util = require('util');

// if on OpenShift, use OpenShift ip/port, else use your local ip/port
var ipAddress = process.env.OPENSHIFT_INTERNAL_IP || process.env.OPENSHIFT_NODEJS_IP || "127.0.0.1";
var port = process.env.OPENSHIFT_INTERNAL_IP || process.env.OPENSHIFT_NODEJS_PORT || 8080;

http.createServer(function (req, res) {

  // This part of code is unchanged, so it's removed to simplify
  // the answer

}).listen(port, ipAddress);  // <<<<< use variables set above
console.log('Server running at ' + ipAddress + ":" + port);

答案 1 :(得分:0)