Question

这应该是一个简单的问题，我不明白为什么会这样：

错误：

尝试通过电动工具生成这些模型时，我收到此错误，当我试图在另一个项目中添加关于这些的迁移时，我也遇到了类似的错误。

Activity_ActivityResult_Target: : Multiplicity is not valid in Role 'Activity_ActivityResult_Target' in relationship 'Activity_ActivityResult'. Because the Dependent Role properties are not the key properties, the upper bound of the multiplicity of the Dependent Role must be '*'.

我们在relationship策略中使用了2个简单的类code-fisrt。

Desired: Activity 1 ----> ActivityResult 0-1

整个代码：

   public class Activity 
    {
        [Key]
        public int Id { get; set; }
        public DateTime? ActivityDate{ get; set;}

        // Tested with and without these commented part, I didn't think it should be
        //[ForeignKey("ActivityResult")]
        //public int? ActivityResultId { get; set; }
       public virtual ActivityResult ActivityResult { get; set; }
    }


    //---------------

    public class ActivityResult //: Entity
    {

        [Key]
        public int Id { get; set; }
        public int Score1 { get; set; }
        public int Score2 { get; set; }

        [ForeignKey("Activity")]
        [Required]
        public int ActivityId { get; set; }
        public virtual Activity Activity { get; set; }
    }

// ---------------

    public class Context : DbContext
    {
        public DbSet<Activity> Activities { get; set; }
        public DbSet<ActivityResult> ActivityResults { get; set; }
    }

为什么呢？解决方案是什么？

Answer 1

在一对一的关系中，外键也是主键。

您需要更改ActivityResult以删除Id属性，并且只有ActivityId。它将包含[Key]和[ForeignKey]：

public class ActivityResult //: Entity
{

    [Key]
    [ForeignKey("Activity")]
    [Required]
    public int ActivityId { get; set; }
    public int Score1 { get; set; }
    public int Score2 { get; set; }

    public virtual Activity Activity { get; set; }
}

以下是Entity Framework如何使用迁移创建表。您会注意到ActivityResults未将ActivityId定义为Identity。这是因为它无法自动生成。为了成为一对一，它必须在“活动”中具有匹配的行。它是主键，因此它是独一无二的。如果你同时拥有ActivityId和Id而Id是主键，那么你真的有一对多的关系。

CreateTable(
    "dbo.Activities",
    c => new
    {
        Id = c.Int(nullable: false, identity: true),
        ActivityDate = c.DateTime(),
    })
    .PrimaryKey(t => t.Id);

CreateTable(
    "dbo.ActivityResults",
    c => new
    {
        ActivityId = c.Int(nullable: false),
        Score1 = c.Int(nullable: false),
        Score2 = c.Int(nullable: false),
    })
    .PrimaryKey(t => t.ActivityId)
    .ForeignKey("dbo.Activities", t => t.ActivityId)
    .Index(t => t.ActivityId);

Answer 2

@Dismissile是对的，但是正确的代码是：

public class Activity {
        [Key]
        public int Id { get; set; }
        public DateTime? ActivityDate { get; set; }
        public virtual ActivityResult ActivityResult { get; set; }
    }


    //---------------

    public class ActivityResult {

        [Key]
        public int Id { get; set; }
        public int Score1 { get; set; }
        public int Score2 { get; set; }

        //public int ActivityId { get; set; }
        [ForeignKey("Id")]
        [Required]
        public virtual Activity Activity { get; set; }
    }

给出以下表格：

CREATE TABLE [dbo].[Activities](
    [Id] [int] IDENTITY(1,1) NOT NULL,
    [ActivityDate] [datetime] NULL,
 CONSTRAINT [PK_dbo.Activities] PRIMARY KEY CLUSTERED 
(
    [Id] ASC
)

和

CREATE TABLE [dbo].[ActivityResults](
    [Id] [int] NOT NULL,
    [Score1] [int] NOT NULL,
    [Score2] [int] NOT NULL,
 CONSTRAINT [PK_dbo.ActivityResults] PRIMARY KEY CLUSTERED 
(
    [Id] ASC
)

Code-First关系 - 关于Multiplicity的关注错误

2 个答案: