Question

当我只想在blankspace之前使用：＆＃39; cin >> buffer读取字符时，此程序有效。但是，我想读取用户输入的所有内容，包括空格。所以，我改变了使用＆＃34;＆gt;＆gt;＆＃34;打个电话。我似乎传递了正确的参数，我已经完成了#include和#include。编译时的错误消息是：

Driver.cpp：在函数'int main（int，char * const *）'中： Driver.cpp：49：44：错误：没有匹配的函数来调用 'getline（std :: istream＆amp;，char [1024]）' getline（cin，buffer）; ^ Driver.cpp:49:44：注意：候选人是：/usr/include/wchar.h:4:0中包含的文件，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/cwchar:44，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/bits/postypes.h:40，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/iosfwd:40，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/ios:38，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/ostream:38，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/iostream:39，来自Driver.cpp：1：/usr/include/sys/stdio.h:37:9：注意：ssize_t getline（char **，size_t *，FILE *）ssize_t _EXFUN（getline，（char **，size_t *，FILE *））; ^ /usr/include/sys/stdio.h:37:9：注意：候选人需要3个参数，2个提供的文件包含在 /usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/string:52:0，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/bits/locale_classes.h:40，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/bits/ios_base.h:41，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/ios:42，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/ostream:38，来自/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/iostream:39，来自Driver.cpp：1：/usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/bits/basic_string.h:2793:5：注意：模板 std :: basic_istream＆lt; _CharT，_Traits＆gt;＆amp; std :: getline（std :: basic_istream＆lt; _CharT，_Traits＆gt;＆amp ;, std :: basic_string＆lt; _CharT，_Traits，_Alloc＆gt;＆amp;） getline（basic_istream＆lt; _CharT，_Traits＆gt;＆amp; __is， ^
 ^ /usr/lib/gcc/x86_64-pc-cygwin/4.8.2/include/c++/bits/basic_string.tcc:1068:5:
注意：模板参数扣除/替换失败： Driver.cpp：49：44：注意：不匹配的类型'std :: basic_string＆lt; _CharT， _Traits，_Alloc＆gt;'和'char [1024]' getline（cin，buffer）; ^ Makefile：24：目标配方＆＃39; Driver.o＆＃39;失败的make： * [Driver.o]错误1

以下是删除了一些代码的代码：

#include <iostream>
#include <cstdio>
#include <string>
#include <getopt.h>
#include "Driver.hpp"
#include "SymTab.hpp"

using namespace std;

#ifdef NULL
#undef NULL
#define NULL 0
#endif

ostream & operator << (ostream & stream, const Student & stu) {
        return stream << "name:  " << stu.name
                << " with studentnum:  " << stu.studentnum;
}

int main (int argc, char * const * argv) {
        char buffer[BUFSIZ];
        char command;
        long number;
        char option;

        while ((option = getopt (argc, argv, "x")) != EOF) {

        switch (option) {
                case 'x': SymTab<Student>::Set_Debug_On ();
                        break;
                }       
        }

        SymTab<Student> ST;
        ST.Write (cout << "Initial Symbol Table:\n" );

        while (cin) {
                command = NULL;         // reset command each time in loop
                cout << "Please enter a command ((i)nsert, "
                        << "(l)ookup, (r)emove, (w)rite):  ";
                cin >> command;

                switch (command) {

                case 'i': {
                        cout << "Please enter student name to insert:  ";
                        getline(cin, buffer);

                        cout << "Please enter student number:  ";
                        cin >> number;

                        Student stu (buffer, number);

                        // create student and place in symbol table
                        ST.Insert (stu);
                        break;
                }

        }

        ST.Write (cout << "\nFinal Symbol Table:\n");
}

这是我的第一篇文章，所以请告诉我是否搞砸了我的格式，如果需要更多信息来帮助我。谢谢！

Answer 1

std::getline()的所有重载都需要(basic) istream和string。要解决此问题，请将char buffer []更改为std::string buffer并记住#include <string>。

getline没有匹配功能

1 个答案: