Question

每当我尝试构建此代码时，我都会收到错误，

“没有用于调用getline（）的匹配函数”

但我以前用过它并且工作正常吗？我不确定发生了什么事。我正在使用Mavericks OSX，如果有的话，并使用Xcode来构建这个项目。这是为了学校。我知道inputFile工作正常，因为我已经注释了打印到控制台的getline（）和“Open”。

//
//  main.cpp
//  Project 4
//
//  Created by Eric Diviney on 10/27/13.
//  Copyright (c) 2013 Eric Diviney. All rights reserved.
//

#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
using namespace std;

int main()
{
    /*
    |
    |-------------------------------------------------------------
    |   Documentation
    |-------------------------------------------------------------
    |   The headings[] array will contain all strings for the customer's receipt.
    |   the 2nd level of headings[][] will contain all of the info (name, address etc.) while
    |   the first level of headings[] will contain the number of customers. The order of the second level is heading1, heading2, customername,
    |   address, phone, footer
    |
    |   The charges[] array will contain all double/floats required to compute the charges for the customer.
    |   The third level of charges[][][] will contain the actual charges/prices while the first level
    |   will hold n amount of customers. The second level of that array (charges[][]) will hold the first, second and third month.
    |   The order of the last array is electricity, water, and gas
    |
    |   The output[] array is 3 customers in the first level (output[]) and the correspnding strings for each
    |   segment of their receipt output[][]. The order in the second level of this array is heading1, heading2, customerName, Customer address, 
    |   customer Phone, Customer ID, electricity, water, gas, subtotal, discountRate, taxRate, tax for order, discount for order, order total,
    |   footer
    |
     */

    // variable declarations
    string headings[3][7];
    double charges[3][3][3];
    string output[3][16];

    ifstream inputFile;
    inputFile.open("/Users/ericdiviney/Documents/workspace/project4/project4/input.txt");
    if(inputFile.is_open())
    {
        cout << "Open" << endl;
    }

    getline(inputFile, headings[0][0], "*");
    //cout << headings[0][0];

  return 0;
}

Answer 1

第三个参数是单个字符，因此您需要

getline(inputFile, headings[0][0], '*');

请注意单引号。 "*"是以null结尾的字符串文字，类型为const char[2]。

调用getline（）没有匹配函数？

1 个答案: