我正在尝试在Tomcat 7上创建和部署一个简单的Web服务（在我的机器上本地）。它是一个Java Servlet，用于将图像上传到服务器，将其本地存储在某个目录中，然后在我的Servlet中调用下游的另一个函数。
尝试将图像发布到servlet时，我遇到了这个错误：
HTTP Status 405 - HTTP method POST is not supported by this URL
type Status report
message HTTP method POST is not supported by this URL
description The specified HTTP method is not allowed for the requested resource.
我跟踪了几个相关的帖子，讨论了同样的问题，但我无法缩小这个问题的范围。任何帮助将不胜感激。
UploadServlet.java
package com.apps.servlets;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItemStream;
import org.apache.commons.fileupload.FileItemIterator;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import com.apps.services.SearchByURL;
import java.io.FileOutputStream;
import java.io.InputStream;
import java.io.File;
import java.io.OutputStream;
public class UploadServlet extends HttpServlet {
private String filePath;
private File file;
private String bestGuessString;
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
bestGuessString = "";
filePath = getServletContext().getInitParameter("file-upload");
System.out.println("filePath: " + filePath);
filePath = getServletContext().getRealPath(filePath);
System.out.println("filePath2: " + filePath);
String fileName = "";
try {
ServletFileUpload upload = new ServletFileUpload();
FileItemIterator iterator = upload.getItemIterator(request);
while (iterator.hasNext()) {
FileItemStream item = iterator.next();
InputStream stream = item.openStream();
OutputStream outputStream = null;
if (item.isFormField()) {
System.out.println("Got a form field: "
+ item.getFieldName());
} else {
System.out.println("Got an uploaded file: "
+ item.getFieldName() + ", name = "
+ item.getName());
fileName = item.getName();
System.out.println("Absolute path: " + filePath + "/"
+ fileName);
outputStream = new FileOutputStream(new File(fileName));
int len;
byte[] buffer = new byte[8192];
while ((len = stream.read(buffer, 0, buffer.length)) != -1) {
response.getOutputStream().write(buffer, 0, len);
outputStream.write(buffer, 0, len);
}
}
}
} catch (Exception ex) {
throw new ServletException(ex);
}
//Downstream logic (I am using the image and passing it to another custom class)
//CustomClass.java is defined separately
String finalGuess = CustomClass.customFunction(fileName);
if (finalGuess.equals(""))
bestGuessString = "Sorry! Google did not find the image interesting enough.. :)";
else
bestGuessString = finalGuess;
//Redirecting the response to doGet and printing the final result there
response.sendRedirect("/UploadServlet?imageUrl=" + bestGuessString);
}
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, java.io.IOException {
String imageUrl = request.getParameter("imageUrl");
response.setHeader("Content-Type", "text/html");
System.out.println("in doGet(), imageUrl: " + imageUrl);
response.getWriter().println("Best Guess: " + bestGuessString);
}
public void init() {
// Get the file location where it would be stored.
filePath = getServletContext().getInitParameter("file-upload");
}
}
的web.xml
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>UploadServlet</servlet-name>
<servlet-class>com.apps.servlets.UploadServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>UploadServlet</servlet-name>
<url-pattern>/UploadServlet</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<context-param>
<description>Location to store uploaded file</description>
<param-name>file-upload</param-name>
<param-value>
data
</param-value>
</context-param>
</web-app>
的index.html
<!doctype html>
<html>
<head>
<title>File Uploading Form</title>
</head>
<body>
<h3>File Upload:</h3>
Select a file to upload: <br />
<form
action="UploadServlet" method="post" enctype="multipart/form-data"> <input
type="file" name="file" size="50" /> <br /> <input type="submit" value="Upload
File" /> </form>
</body>
</html>
的pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.apps.innovative</groupId>
<artifactId>VoyagerServices</artifactId>
<packaging>war</packaging>
<version>1.0</version>
<name>VoyagerServices Maven Webapp</name>
<url>http://maven.apache.org</url>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>servlet-api</artifactId>
<version>2.5</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.0-alpha4</version>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpcore</artifactId>
<version>4.3.2</version>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpmime</artifactId>
<version>4.3.4</version>
</dependency>
<dependency>
<groupId>org.apache.james</groupId>
<artifactId>apache-mime4j</artifactId>
<version>0.6.1</version>
</dependency>
<dependency>
<groupId>commons-logging</groupId>
<artifactId>commons-logging</artifactId>
<version>1.1.3</version>
</dependency>
<dependency>
<groupId>commons-fileupload</groupId>
<artifactId>commons-fileupload</artifactId>
<version>1.2.1</version>
</dependency>
<dependency>
<groupId>commons-io</groupId>
<artifactId>commons-io</artifactId>
<version>2.4</version>
</dependency>
</dependencies>
<build>
<plugins>
<!-- Maven Tomcat Plugin -->
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>tomcat-maven-plugin</artifactId>
<configuration>
<url>http://127.0.0.1:8080/manager/html</url>
<server>TomcatServer</server>
<path>/VoyagerServices</path>
<username>admin</username>
<password>password</password>
</configuration>
</plugin>
<!-- Maven compiler plugin -->
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.6</source>
<target>1.6</target>
</configuration>
</plugin>
</plugins>
</build>
</project>
答案 0 :(得分：-2)
**html code**
<!DOCTYPE html>
<html lang="en">
<head>
<title>File Upload</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>
<form method="POST" action="upload" enctype="multipart/form-data" >
File:
<input type="file" name="file" id="file" /> <br/>
Destination:
<input type="text" value="/tmp" name="destination"/>
</br>
<input type="submit" value="Upload" name="upload" id="upload" />
</form>
</body>
</html>
**servlet code**
package servlet;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.servlet.ServletException;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.Part;
@WebServlet(name = "FileUploadServlet", urlPatterns = {"/upload"})
@MultipartConfig
public class FileUploadServlet extends HttpServlet {
private final static Logger LOGGER
= Logger.getLogger(FileUploadServlet.class.getCanonicalName());
protected void processRequest(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
// Create path components to save the file
final String path = request.getParameter("destination");
final Part filePart = request.getPart("file");
final String fileName = getFileName(filePart);
OutputStream out = null;
InputStream filecontent = null;
final PrintWriter writer = response.getWriter();
try {
out = new FileOutputStream(new File(path + File.separator
+ fileName));
filecontent = filePart.getInputStream();
int read = 0;
final byte[] bytes = new byte[1024];
while ((read = filecontent.read(bytes)) != -1) {
out.write(bytes, 0, read);
}
writer.println("New file " + fileName + " created at " + path);
LOGGER.log(Level.INFO, "File{0}being uploaded to {1}",
new Object[]{fileName, path});
} catch (FileNotFoundException fne) {
writer.println("You either did not specify a file to upload or are "
+ "trying to upload a file to a protected or nonexistent "
+ "location.");
writer.println("<br/> ERROR: " + fne.getMessage());
LOGGER.log(Level.SEVERE, "Problems during file upload. Error: {0}",
new Object[]{fne.getMessage()});
} finally {
if (out != null) {
out.close();
}
if (filecontent != null) {
filecontent.close();
}
if (writer != null) {
writer.close();
}
}
}
private String getFileName(final Part part) {
final String partHeader = part.getHeader("content-disposition");
LOGGER.log(Level.INFO, "Part Header = {0}", partHeader);
for (String content : part.getHeader("content-disposition").split(";")) {
if (content.trim().startsWith("filename")) {
return content.substring(
content.indexOf('=') + 1).trim().replace("\"", "");
}
}
return null;
}
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
@Override
public String getServletInfo() {
return "Short description";
}// </editor-fold>
}
**Also Check this Link**
http://multiplejava.blogspot.in/2015/03/upload-files-to-server-via-java-servlet.html
[还检查此链接]