tomcat7上的servlet eclipse HTTP状态405 - HTTP方法此URL不支持POST

时间:2014-01-30 20:18:44

标签: java eclipse tomcat servlets post

我是servlet / jsp / portlet tecnology的新手,我正在努力理解,所以我说这个servlet有问题:


package trekking;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class Login
 */
public class Login extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * see HttpServlet#HttpServlet()
     */
    public Login() {
    }

    /**
     * @param name 
     * @param pass 
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     * 
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response, String name, String pass) throws ServletException, IOException {
String u,p;
        u=request.getParameter(name);
        p=request.getParameter(pass);
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();
        out.println("<html>");
        out.println("<head>");
        out.println("<title>Hello World!</title>");
        out.println("You are "+u+"!");
        out.println("</head>");
        out.println("<body>");
        out.println("<h1>Hello World!</h1>");
        out.println("</body>");
        out.println("</html>");
    }
}

通过以下形式在html页面中调用它:

<form action="Login" method="post">
<label for="uname">UserName</label>
<input name="user" id="uname" type="text"></input>
<label for="pwd">Password</label>
<input name="pass" id="pwd" type="password"></input>
<input type="submit" value="invia">
</form>

如果你还需要别的东西,我就在这里。 谢谢。 :d

2 个答案:

答案 0 :(得分:2)

您尚未覆盖doPost方法。你已经超负荷了。

protected void doPost(HttpServletRequest request, HttpServletResponse response, String name, String pass) throws ServletException, IOException {

由于没有任何东西正在调用您的重载方法,因此您将获得默认的继承HttpServlet#doPost()行为,返回405.

答案 1 :(得分:0)

从doPost方法中删除'name'和'pass'参数。