Question

我需要帮助弄清楚如何循环源对象以获取输出字符串。我目前有一些嵌套for循环，但我最终错过了其中一个组合，或者我得到了太多。类别和过滤器的数量会有所不同

源对象

var Source = {Cat1:{Filter1:'f1',Filter2:'f2'},
              Cat2:{Filter3:'f3',Filter4:'f4'},
              Cat3:{Filter5:'f5'}};

输出字符串

Filter1 Filter3 Filter5,
Filter1 Filter4 Filter5,
Filter2 Filter3 Filter5,
Filter2 Filter4 Filter5

Answer 1

试试这个，这将返回数组数组：

function cartesianProduct(paramArray) {

  function addTo(curr, args) {

    var i, copy, 
        rest = args.slice(1),
        last = !rest.length,
        result = [];

    for (i = 0; i < args[0].length; i++) {

      copy = curr.slice();
      copy.push(args[0][i]);

      if (last) {
        result.push(copy);

      } else {
        result = result.concat(addTo(copy, rest));
      }
    }

    return result;
  }


  return addTo([], Array.prototype.slice.call(arguments));
};

var Source = {Cat1:{Filter1:'f1',Filter2:'f2'},
              Cat2:{Filter3:'f3',Filter4:'f4'},
              Cat3:{Filter5:'f5'}};

// var cats = [];
var filters = [];

for(var c in Source) {
  filters.push([]);
  for(var f in Source[c])
    filters[filters.length - 1].push(f);
}


console.log(cartesianProduct.apply(this || window, filters));

HTH

Javascript复杂分组

1 个答案: