Question

以下是我的模特：

class Location(models.Model):
    city = models.CharField()

class Competition(models.Model):
    name = models.CharField()
    location = models.ForeignKey(Location)

class Laureate(models.Model):
    name = models.CharField()
    competitions = models.ManyToManyField(Competition, through='LaureateCompetition')

class LaureateCompetition(models.Model):
    laureate = models.ForeignKey(Laureate)
    competition = models.ForeignKey(Competition)

我正在使用PostgreSQL。我正在尝试根据Laureates对<{1}}进行分组：

Location

我最终做的是这样的：

[
    {
        "city": "Moscow",
        "laureates" : ["Bob", "Peter", "Maria"]
    },
    {
        "city": "London",
        "laureates" : ["Nicolai", "John", "Adam"]
    }
]

如果我使用SQL：

locations = []
all_laureate_competitions = LaureateCompetition.objects.select_related().all()
all_competitions = Competition.objects.order_by('location')\
                                      .distinct('location')\
                                      .select_related()

for competition in list(all_competitions):
    location = competition.location
    competitions = list(set(
        [x for x in all_laureate_competitions
         if x.competition.location == location]
    ))
    laureates = list(set([x.name for x in competitions]))
    locations.append(create_location(location, laureates))
return locations

我真的不喜欢第一种方法。进行此类查询的常见实践是什么？我应该用原始sql做吗？还有更多的方式吗？

Answer 1

你可以这样做：

results = []

for location in Location.objects.all():
    for competition in location.competition_set.all():
        for laurete_competition in competition.laurete_competition_set.all():
            results.append(laurete_competition.laurete_set.all())

print results

另见优秀的Django文档，当我遇到类似的问题时，我总是去那里：
https://docs.djangoproject.com/en/dev/topics/db/models/#extra-fields-on-many-to-many-relationships

Django复杂的分组

1 个答案: