Question

我正在尝试构建一个字典，其中包含输入文件中出现的唯一单词以及每个唯一单词的行号。这就是我到目前为止所拥有的。

def unique_word_index():
    line_no = 0
    word_set=set()
    line_no_set=set()
    word_map = {}
    for line in input_file:

       word_lst=line.strip().split()
       word_lst=[w.lower().strip(string.punctuation) for w in word_lst]
       line_no += 1

       for word in word_lst:
           if word !="":
               line_no_set.add(line_no)
           if 'word' in word_map.keys():
                word_map['word']=line_no_set
           else:
                word_map['word']=''

Answer 1

请尝试以下代码：

def unique_words(input_file):
    file = open(input_file)
    wordlist = {}
    dups = []
    copy = []
    for index, value in enumerate(file):
        words = value.split()
        for word in words:
            wordlist[word] = index
            dups.append(word)
    for word in dups:
        if dups.count(word) != 1 and word not in copy:
            del(wordlist[word])
            copy.append(word)
    for item in wordlist:
        print 'The unique word '+item+' occurs on line '+str(wordlist[item])

它将所有值添加到dict和列表中，然后运行到列表以确保每个值仅出现一次。如果没有，我们会从dict中删除它，只留下唯一的数据。

运行如下：

>>> unique_words('test.txt')
The unique word them occurs on line 2
The unique word I occurs on line 1
The unique word there occurs on line 0
The unique word some occurs on line 2
The unique word times occurs on line 3
The unique word say occurs on line 2
The unique word too occurs on line 3
The unique word have occurs on line 1
The unique word of occurs on line 2
>>>

Answer 2

你可以这样：

def unique_words(input_file):
    word_map = dict()
    for i, line in enumerate(input_file):
        words = line.strip().split()
        for word in words:
            word = word.lower().strip(string.punctuation)
            if word in word_map:
                word_map[word] = None
            else:
                word_map[word] = i
    return dict((w, i) for w, i in word_map.items() if i is not None)

它将单词及其对应的行号添加到字典word_map中。当一个单词被多次出现时，其行号将被None替换。最后一行删除行号为None的条目。

现在是使用Counter的紧凑版本：

from collections import Counter

def unique_words(input_file):
    words = [(i, w.lower().strip(string.punctuation))
            for i, line in enumerate(input_file) for w in line.strip().split()]
    word_counts = Counter(w for _, w in words)
    return dict((w, i) for i, w in words if word_counts[w] == 1)

在字典中存储字符串和集合

2 个答案: