有什么方法可以替换Swift String上的字符吗？

时间：2014-06-13 08:28:40

标签： ios swift string

我正在寻找一种替换Swift String中的字符的方法。

示例："This is my string"

我想将替换为+以获取："This+is+my+string"。

我怎样才能做到这一点？

22 个答案:

答案 0 :(得分：808)

此答案已针对Swift 4进行了更新。如果您仍在使用Swift 1,2或3，请查看修订历史记录。

你有几个选择。您可以按@jaumard建议并使用replacingOccurrences() 

let aString = "This is my string"
let newString = aString.replacingOccurrences(of: " ", with: "+", options: .literal, range: nil)

如下面的@cprcrack所述，options和range参数是可选的，因此如果您不想指定字符串比较选项或范围来进行替换，则只需需要以下内容。

let aString = "This is my string"
let newString = aString.replacingOccurrences(of: " ", with: "+")

或者，如果数据采用这样的特定格式，您只需要替换分隔字符，则可以使用components()将字符串分解为数组，然后可以使用{{1函数将它们与指定的分隔符一起放回。

join()

或者，如果您正在寻找更多不使用NSString API的Swifty解决方案，您可以使用它。

let toArray = aString.components(separatedBy: " ")
let backToString = toArray.joined(separator: "+")

答案 1 :(得分：60)

您可以使用：

let s = "This is my string"
let modified = s.replace(" ", withString:"+")

如果您在代码中的任何位置添加此扩展方法：

extension String
{
    func replace(target: String, withString: String) -> String
    {
       return self.stringByReplacingOccurrencesOfString(target, withString: withString, options: NSStringCompareOptions.LiteralSearch, range: nil)
    }
}

斯威夫特3：

extension String
{
    func replace(target: String, withString: String) -> String
    {
        return self.replacingOccurrences(of: target, with: withString, options: NSString.CompareOptions.literal, range: nil)
    }
}

答案 2 :(得分：44)

Swift 3，Swift 4，Swift 5解决方案 

let exampleString = "Example string"

//Solution suggested above in Swift 3.0
let stringToArray = exampleString.components(separatedBy: " ")
let stringFromArray = stringToArray.joined(separator: "+")

//Swiftiest solution
let swiftyString = exampleString.replacingOccurrences(of: " ", with: "+")

答案 3 :(得分：18)

你测试过这个：

var test = "This is my string"

let replaced = test.stringByReplacingOccurrencesOfString(" ", withString: "+", options: nil, range: nil)

答案 4 :(得分：13)

斯威夫特4：

let abc = "Hello world"

let result = abc.replacingOccurrences(of: " ", with: "_", 
    options: NSString.CompareOptions.literal, range:nil)

print(result :\(result))

输出：

result : Hello_world

答案 5 :(得分：8)

符合Sunkas的Swift 3解决方案：

extension String {
    mutating func replace(_ originalString:String, with newString:String) {
        self = self.replacingOccurrences(of: originalString, with: newString)
    }
}

使用：

var string = "foo!"
string.replace("!", with: "?")
print(string)

输出：

foo?

答案 6 :(得分：7)

我正在使用此扩展程序：

extension String {

    func replaceCharacters(characters: String, toSeparator: String) -> String {
        let characterSet = NSCharacterSet(charactersInString: characters)
        let components = self.componentsSeparatedByCharactersInSet(characterSet)
        let result = components.joinWithSeparator("")
        return result
    }

    func wipeCharacters(characters: String) -> String {
        return self.replaceCharacters(characters, toSeparator: "")
    }
}

用法：

let token = "<34353 43434>"
token.replaceCharacters("< >", toString:"+")

答案 7 :(得分：6)

修改现有可变字符串的类别：

extension String
{
    mutating func replace(originalString:String, withString newString:String)
    {
        let replacedString = self.stringByReplacingOccurrencesOfString(originalString, withString: newString, options: nil, range: nil)
        self = replacedString
    }
}

使用：

name.replace(" ", withString: "+")

答案 8 :(得分：4)

基于Ramis' answer的Swift 3解决方案：

extension String {
    func withReplacedCharacters(_ characters: String, by separator: String) -> String {
        let characterSet = CharacterSet(charactersIn: characters)
        return components(separatedBy: characterSet).joined(separator: separator)
    }
}

尝试根据Swift 3命名约定提出适当的函数名称。

答案 9 :(得分：2)

var str = "This is my string"
str = str.replacingOccurrences(of: " ", with: "+")
print(str)

答案 10 :(得分：1)

以下是Swift 3的示例：

var stringToReplace = "This my string"
if let range = stringToReplace.range(of: "my") {
   stringToReplace?.replaceSubrange(range, with: "your")
}

答案 11 :(得分：1)

这在Swift 4.2中很容易。只需使用replacingOccurrences(of: " ", with: "_")进行替换

var myStr = "This is my string"
let replaced = myStr.replacingOccurrences(of: " ", with: "_")
print(replaced)

答案 12 :(得分：1)

Xcode 11•Swift 5.1

StringProtocol replacingOccurrences的变异方法可以实现如下：

extension RangeReplaceableCollection where Self: StringProtocol {
    mutating func replaceOccurrences<Target: StringProtocol, Replacement: StringProtocol>(of target: Target, with replacement: Replacement, options: String.CompareOptions = [], range searchRange: Range<String.Index>? = nil) {
        self = .init(replacingOccurrences(of: target, with: replacement, options: options, range: searchRange))
    }
}

var name = "This is my string"
name.replaceOccurrences(of: " ", with: "+")
print(name) // "This+is+my+string\n"

答案 13 :(得分：0)

我已经实现了这个非常简单的功能：

func convap (text : String) -> String {
    return text.stringByReplacingOccurrencesOfString("'", withString: "''")
}

所以你可以写：

let sqlQuery = "INSERT INTO myTable (Field1, Field2) VALUES ('\(convap(value1))','\(convap(value2)')

答案 14 :(得分：0)

我认为Regex是最灵活，最可靠的方式：

var str = "This is my string"
let regex = try! NSRegularExpression(pattern: " ", options: [])
let output = regex.stringByReplacingMatchesInString(
    str,
    options: [],
    range: NSRange(location: 0, length: str.characters.count),
    withTemplate: "+"
)
// output: "This+is+my+string"

答案 15 :(得分：0)

快速扩展： 

extension String {

    func stringByReplacing(replaceStrings set: [String], with: String) -> String {
        var stringObject = self
        for string in set {
            stringObject = self.stringByReplacingOccurrencesOfString(string, withString: with)
        }
        return stringObject
    }

}

继续使用let replacedString = yorString.stringByReplacing(replaceStrings: [" ","?","."], with: "+")

这个功能的速度是我很难引以为傲的，但你可以在一遍中传递一个String数组来进行多次替换。

答案 16 :(得分：0)

如果您不想使用Objective-C NSString方法，则可以使用split和join：

var string = "This is my string"
string = join("+", split(string, isSeparator: { $0 == " " }))

split(string, isSeparator: { $0 == " " })返回一个字符串数组（["This", "is", "my", "string"]）。

join使用+加入这些元素，从而产生所需的输出："This+is+my+string"。

答案 17 :(得分：0)

很少发生在我身上，我只想更改String中的（单词或字符）

所以我用了Dictionary 

  extension String{
    func replaceDictionary(_ dictionary: [String: String]) -> String{
          var result = String()
          var i = -1
          for (of , with): (String, String)in dictionary{
              i += 1
              if i<1{
                  result = self.replacingOccurrences(of: of, with: with)
              }else{
                  result = result.replacingOccurrences(of: of, with: with)
              }
          }
        return result
     }
    }

用法

let mobile = "+1 (800) 444-9999"
let dictionary = ["+": "00", " ": "", "(": "", ")": "", "-": ""]
let mobileResult = mobile.replaceDictionary(dictionary)
print(mobileResult) // 001800444999

答案 18 :(得分：0)

您可以对此进行测试：

let newString = test.stringByReplacingOccurrencesOfString（“”，withString：“ +”，选项：无，范围：无）

答案 19 :(得分：0)

const serviceClient = new ShareServiceClient(
      `https://${storageAccountName}.file.core.windows.net`,
      credential
    );
    const directoryClient  = serviceClient.getShareClient(shareName).getDirectoryClient(directoryPath);
    const dirIter = directoryClient.listFilesAndDirectories();
    const list = [];
    for await (const item of dirIter) {
        list.push({name: item.name, metadata????}); // Need item metadata 
    }

输出为

var str = "This is my string"

print(str.replacingOccurrences(of: " ", with: "+"))

答案 20 :(得分：0)

从 Swift 2 开始，String 不再符合 SequenceType。换句话说，您不能使用 for...in 循环遍历字符串。

简单易行的方法是将 String 转换为 Array 以获得索引的好处，就像这样：

let input = Array(str)

我记得当我试图在不使用任何转换的情况下索引到 String 时。我真的很沮丧，我无法想出或达到想要的结果，并准备放弃。 但我最终创建了自己的解决方案，这是扩展的完整代码：

extension String {
    subscript (_ index: Int) -> String {
    
        get {
             String(self[self.index(startIndex, offsetBy: index)])
        }
    
        set {
            remove(at: self.index(self.startIndex, offsetBy: index))
            insert(Character(newValue), at: self.index(self.startIndex, offsetBy: index))
        }
    }
}

现在您可以使用字符串的索引读取和替换字符串中的单个字符，就像您最初想要的那样：

var str = "cat"
for i in 0..<str.count {
 if str[i] == "c" {
   str[i] = "h"
 }
}

print(str)

使用它并通过 Swift 的 String 访问模型是一种简单而有用的方法。 现在，当您可以按原样循环遍历字符串而不是将其转换为 Array 时，下次您会感觉一切顺利。

试试看，看看是否有帮助！

答案 21 :(得分：-1)

以下是var r = {"meta":{"code":200,"requestId":"595cc7784c1f67701d721227"},"response":{"venues":[{"id":"5564370c498e52484ec3249f","name":"Aras Döner & Kokoreç","contact":{},"location":{"lat":41.187417726573926,"lng":27.76829713785891,"labeledLatLngs":[{"label":"display","lat":41.187417726573926,"lng":27.76829713785891}],"distance":12,"cc":"TR","country":"Türkiye","formattedAddress":["Türkiye"]},"categories":[{"id":"4bf58dd8d48988d16e941735","name":"Fast Food Restoranı","pluralName":"Fast Food Restoranları","shortName":"Fast Food","icon":{"prefix":"https:\/\/ss3.4sqi.net\/img\/categories_v2\/food\/fastfood_","suffix":".png"},"primary":true}],"verified":false,"stats":{"checkinsCount":2038,"usersCount":740,"tipCount":0},"allowMenuUrlEdit":true,"beenHere":{"lastCheckinExpiredAt":0},"specials":{"count":0,"items":[]},"hereNow":{"count":0,"summary":"Burada kimse yok","groups":[]},"referralId":"v-1499252600","venueChains":[],"hasPerk":false}],"confident":false}}; var venues = r.response.venues; for (i = 0; i < venues.length; i++) { console.log(venues[i].name) } 上的就地出现替换方法的扩展，它不会产生不必要的副本，并且可以执行所有操作：

String

（方法签名也模仿内置extension String { mutating func replaceOccurrences<Target: StringProtocol, Replacement: StringProtocol>(of target: Target, with replacement: Replacement, options: String.CompareOptions = [], locale: Locale? = nil) { var range: Range<Index>? repeat { range = self.range(of: target, options: options, range: range.map { self.index($0.lowerBound, offsetBy: replacement.count)..<self.endIndex }, locale: locale) if let range = range { self.replaceSubrange(range, with: replacement) } } while range != nil } } 方法的签名）

可以按以下方式使用：

String.replacingOccurrences()
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