我正在学习异常..示例代码的目的是创建一个合适的对象。 这就是......
#include <iostream>
#include <exception>
#include <string>
#include <stdexcept>
using std::string;
using std::invalid_argument;
using std::cin;
using std::cout;
using std::endl;
class Person
{
public:
Person(){}
Person(string name, int age)
{
if (age < 18)
throw invalid_argument(name + " is minor!!!");
if (name.empty())
throw invalid_argument("Name can't be empty");
_name = name;
_age = age;
}
Person(Person&& that) : _name(std::move(that._name))
{
_age = that._age;
that._name.clear();
}
Person& operator=(Person&& that)
{
_name = std::move(that._name);
_age = that._age;
that._name.clear();
return *this;
}
Person(const Person& that)
{
_age = that._age;
_name = that._name;
}
Person& operator=(const Person& that)
{
_name = that._name;
_age = that._age;
return *this;
}
~Person() { cout << "In person destructor"; }
string getName(void) const { return _name; }
private:
string _name;
int _age;
};
Person createPerson()
{
try
{
string name;
int age;
cout << "Enter name of the person: ";
cin >> name;
cout << "Enter age of the person: ";
cin >> age;
Person aNewPerson(name, age);
return aNewPerson;
}
catch (invalid_argument& e)
{
cout << e.what() << endl;
cout << "Please try again!!!" << endl;
}
}
int main(void)
{
Person aNewPerson;
aNewPerson = createPerson();
cout << aNewPerson.getName() << " created" << endl;
return 0;
}
我只想在构造正确的对象时退出程序。 例如,如果我输入名称为APerson并且年龄为1,则抛出异常。 但是,我想继续创建对象并在成功创建对象后退出程序。
我没有得到怎么做。 有人可以帮忙吗? 感谢。
答案 0 :(得分:0)
好的,我得到了答案,如果我错了请纠正我... 我像这样修改了createPerson()函数......
Person createPerson()
{
while (1)
{
try
{
string name;
int age;
cout << "Enter name of the person: ";
cin >> name;
cout << "Enter age of the person: ";
cin >> age;
Person aNewPerson(name, age);
return aNewPerson;
}
catch (invalid_argument& e)
{
cout << e.what() << endl;
cout << "Please try again!!!" << endl;
}
}
}