我正在尝试存储第三方网站的用户oauth详细信息,BaseConnection表用于存储连接的基本信息
class BaseConnection(Base):
__tablename__ = "BaseConnection"
id = Column(Integer, primary_key=True)
username = Column(Unicode(255),
ForeignKey('users.username'))
type = Column(Unicode(255))
is_active = Column(Boolean, default=False)
last_connection = Column(DateTime, onupdate=datetime.utcnow)
__mapper_args__ = {
'polymorphic_identity': 'BaseConnection',
'polymorphic_on': type
}
def __init__(self, username, type, is_active):
self.username = username
self.type = type
self.is_active = is_active
Twitter连接用于存储Twitter帐户的详细信息
class TwitterConnection(Base):
__tablename__ = "TwitterConnection"
connection_id = Column(Integer, ForeignKey('BaseConnection.id'),
primary_key=True)
uid = Column(Unicode(255))
access_key = Column(Unicode(255))
access_secret = Column(Unicode(255))
twitter_username = Column(Unicode(255))
refresh_date = Column(DateTime)
__mapper_args__ = {
'polymorphic_identity': 'TwitterConnection'
}
def __init__(self, connection_id,
uid, access_key, access_secret, twitter_username):
self.connection_id = connection_id
self.uid = uid
self.access_key = access_key
self.access_secret = access_secret
self.twitter_username = twitter_username
self.refresh_date = datetime.now()
然后我使用代码
将第一个细节添加到表中base_connection = BaseConnection('admin', TwitterConnection.__name__, True)
base_connection.last_connection = datetime.now()
DBSession.add(base_connection)
DBSession.flush()
tconnection = TwitterConnection(
base_connection.id,
uid=u'1234',
access_key=u'dummy',
access_secret=u'dummy',
twitter_username='dummy')
DBSession.add(tconnection)
DBSession.flush()
transaction.commit()
我尝试编写查询以查找具有特定用户名的用户的所有第三方帐户
qry = BaseConnection.query.filter(
BaseConnection.username==username)
qry.all()
以上查询给出了错误
`AssertionError: No such polymorphic_identity u'TwitterConnection' is defined
我是sqlalchemy的新手,感谢您的帮助。谢谢。
答案 0 :(得分:2)
对不起,
class TwitterConnection(Base):
应该是
class TwitterConnection(BaseConnection):